What lines do not have equations in slope-intercept form? What lines do not have equations in standard form?
slope-intercept form is y = mx + b where m is slope and b is y-intercept. A vertical line has undefined slope so it cannot be put into slope-intercept form. A horizontal line has a slope of 0 so it can be put into slope-intercept form All lines can be put to standard form^_^
Write the linear equation in slope-intercept form 5x+6y-17=0?
slope intercept form is y = mx + b, where m is the slope and b is the y-intercept. Notice it is solved for y, so just solve the equation for y. 1. add 17 to both sides: 5x + 6y = 17 2. subtract 5x from both sides: 6y = -5x + 17 (notice the x term is in front of the 17) 3. divide everything by 6: y = -5/6 x + 17/6
What is the slope and y-intercept of the equation: 6x - 2y = 18?
6x - 2y = 18Put the equation in “slope-intercept form” where the “y” variable is solved for.-2y = 18 - 6x-2y = -6x + 18y = 3x - 9Once it’s in this form, you can find the slope (m) and the y-intercept (b).y = mx + bSlope = 3, y-intercept = (0,-9).
In the equation 8y+3x=-48, can you find the x- and y-intercept and the slope? How do I solve this problem?
8y+3x=-48……………(1)1st Method:Let ‘a’ be the x-intercept of the straight line and ‘b’ be the y-intercept. Then the straight line must pass through the two points P(a,0) and Q(0,b).Now, putting x=a and y=0 in equation(1), we obtain, 3a=-48, or, a=-16. So, the x-intercept of the straight line is=a=-16. So, the length of ththx-intercept is=|a|=|-16|=16.Similarly, putting x=0 and y=b in equation(1), we get, 8b=-48 , or, b=-6. So, the straight line passes through the point Q(0,-6) and so its y-intercept is=b=-6 and the length of y-intercept is=|b|=|-6|=6.2nd Method:Dividing both sides of equation(1) by -48, we obtain,x/(-16)+y/(-6)=1So, for the straight line under consideration, x-intercept is= -16 and y-intercept= -6.[Corresponding theory: If ‘a’ and ‘b’ are the x-intercept and y-intercept of a straight line respectively, then it must pass through the points (a,0) and (0,b) and its equation is: x/a+y/b=1]
Write an equation in slope-intercept form of the line that passes through (2,2) and has a y-intercept of 7?
Slope intercept equation is y=mx+b. If it says you have a y-intercept of 7, the 7 replaces the b because the b is "y-intercept". So now you have y=mx+7. The point (2,2) refers to x and y. So you plug in 2 and 2 for x and y in the equation. 2=m2+7. To solve for m you have to isolate it, so you subtract seven from each side (-5=m2) and then you divide each side by 2 (-5/2=m). Now you have the information for your equation. . .m=-5/2 and b=7! y= -5/2x+7 That's how you do the problems with the example above. There's another kind of question they might ask and that is "Write an equation with the given points - (2,-4) and (4,1). Now what you do here is put those numbers in Point Slope form. And that form is (Y sub 2 - Y sub 1) divided by (X sub 2 - X sub 1). If you plug in those numbers the Y sub and X sub 2's are really the SECOND numbers in the coordinates. . .Y sub 2 is 1 and Y sub 1 is -4. X sub 2 is 4 and and X sub 1 is 2. That equation if you solve it right will give you the slope of the equation. The slope of this equation would be 5/2. Then you plug that in to y=mx+b...y=5/2x+b. To find the X and Y values, use the coordinates of the first ordered pair (2,-4) and plug those in. Then solve for b.
How can I write an equation in standard form given slope and y-intercept?
Standard form is ax + by = c. Slope intercept form is y = mx + b.To convert from slope intercept form to standard form requires you to have x and y on the same side of the equation.y = (2/3)x - 6 slope intercept form. Step one subtract(2/3)x from both sides.-(2/3)x + y = -6 Step 2 get rid of fractions and make the x coefficient positive, multiply each term by -3.2x - 3y = 18 Now in standard form.
Slope and Y-intercept Question?
Ok all you have to do is put it into slope y-intercept form. (y=mx+b) Your m being your slope and b being your y intercept. So right now those two equations are in standard form. What you have to do is bring everything BUT y to one side. Line 1: 2x+y=6. So bring 2x to the other side to isolate y. Which becomes y= - 2x + 6. Remember when bringing a term to the other side the interger changes to it's opposite. Slope is -2 and y intercept is 6. y=mx+b Line 2: 3x-6y-12=0. Bring 3x and -12 to the other side to isolate y. Becomes -6y= - 3x +12. Now your y must be by it's self with now number beside it. So divide -6y by -6 to get y by itself. And if you do that to one side, you do it to the next side as well. So divide -3x by -6 which becomes 3/6 reduced to 1/2 (no negative because 2 negatives cancel out) and 12 divided by -6 which is -2. So y=1/2x - 2
X-intercept= 10 and the slope is 1.5....... How do you put this in slope intercept form?
(10, 0) is a point, so you can use this. y = mx + b 0 = 10(3/2) + b b= -15 y = 3x/2 - 15 or y-1.5x -15 if you prefer.
Can someone explain how to put these into slope intercept form? (y=mx+b)?
first isolate the y monomial on one side (the first one would be 3/5y=-1/5x=12/5) the 2nd two will be done for #1, then multiply each side by 5/3, that way y will be isolated
Given the system find the Y-INTERCEPT of each equation.?
B. -7, 8 ____ y = mx + b is the slope-intercept form of the equation of a line m... slope b.... y-intercept Hope this helps.