Need some help with this chemistry problem?
_____Thermo q = heat released heat released = 4.186J/gC * 2000g water * (40.5 - 24.5)C = ?? J heat released/g = ??J / 5.00g = ??J/g SOLVE Basic mathematics is a prerequisite to chemistry – I just try to help you with the methodology of solving the problem.
I need help on my chemistry hw plz help me chemistry experts plz i really need help any answers would help!?
1.describe the movement of the hydronium ion through an aqueous solution. 2. write an equation for the dissociation of the strong base Ca(OH)2 3. write and equation showing how aniline, C6H5NH2 4. Does ammonia still act like a weak base even when its hydrogen atoms are replaced by organic groups? explain 5. why does the hydronium ion concentration of an aqueous solution decrease when the hydroxide ion concentration incereases? 6.what is the relationship between the strength of an acid and the strength of its conjugate base? 7. what is the relationship between the strength of a base and the strength of its conjugate acid?
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OK, the key here is to note what types of bonds you have on each side of the equation, and the amount of energy in those bonds. Reactants: 12 C-H bonds (6 * 2) - 413 kJ/mol * 12 = 4956 2 C=C bonds (1 * 2) - 614 = 1228 2 C-C bonds (1 * 2) - 348 * 2 = 696 6 N-H bonds (3 * 2) - 391 * 6 = 2346 3 O-O bonds (1 * 3) - 145 * 3 = 435 Total bond energy: 9661 kJ/mol Products: 2 C=C bonds (1 * 2) - 614 = 1228 2 C-C bonds (1 * 2) - 348 * 2 = 696 2 C---N bond (1 * 2) (triple bond) - 890 * 2 = 1780 6 C-H bonds (3 * 2) - 413 kJ/mol * 6 = 2478 12 O-H bonds (6 * 2) - 366 * 12 = 4392 Total: 10574 kJ/mol Thus, the ΔH is 9661 kJ/mol - 10574 kJ/mol = -913 kJ/mol Note: The CN bond in the product must be a triple bond - because nitrogen has a valence of 3, and isn't bonded to anything but the Carbon. The quick alternative, is to only write down the bonds that change during the reaction: Reactants: 6 C-H bonds (6 * 2) - 413 kJ/mol * 6 = 2478 6 N-H bonds (3 * 2) - 391 * 6 = 2346 3 O-O bonds (1 * 3) - 145 * 3 = 435 Total bond energy: 5259 Products: 2 C---N bond (1 * 2) (triple bond) - 890 * 2 = 1780 12 O-H bonds (6 * 2) - 366 * 12 = 4392 Total: 6172 5259 - 6172 = -913 kJ/mol
Bonding experts....chemistry..i need help!?
It is a covalent bond. 1. Most covalent bonds are weak and / or have little intermolecular forces holding the molecules togther - so the melt at low temps 2. Most covalent compounds are non-polar. Water is polar. Non-polar cannot disscolve in polar fuilds 3. You must have charged particles (such as ions) in water to carry electricity. Covalent compunds do not form charged compounds 4. (See number 1)
Chemistry problem need some help?
Can you guys help me with this one question: In each pair of bonds, predict which is shorter. (a) B−Cl or Ga−Cl (b) Sn−O or C−O (c) P−S or P−O (d) C=O or C=N
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The pressure at that point = height*gravitational force*density height= 76/100 = 0.76m grv.force =10N/m2 density = 13.6g/ml = 13600kg/m2 so, P = 0.76*10*13600 = 103 360N/m2 The earth is a sphere and surface area of a sphere of radius r is A = 4 *pi* r^2 = 4*3.14* 6371000 = 80019760m2 Note radius was changed to m from km But pressure is also given by Force/ Area so 103 360 = F / 80 019 760 there4, F = 103 360 * 80 019 760 N But F = mass * grav.force = mass*10 so mass = F/10 = (103 360 * 80 019 760) /10 = .........Kg. My calculator cant get that but its the correct ans. NNNBBBB..Always make sure u r workin with the same units....i.e.if mass is in Kg then make sure density is in Kg/m3 and so on..! If u get it right then am hopin 4 10 points for the work...all the best.
Need some help on my chemistry problem!?
ok, i have this chemistry problem due tomorrow, and i cant figure it out! Element 111 was recently named roentgenium (Rg) by the term of nuclear scientists who produced the element. Calculate the total mass of neutrons in 1 atom of Rg 272 *one neutron has a mass of 1.675 x 10^ -24 g. can someone please help me with this!?
Chemistry problem, need some help.?
1/8 S8(s) + H2(g) ==> H2S(g), ∆Hrxn = -20.2 kJ (a) What is (triangle symbol)Hrxn for the reverse reaction? ∆Hreverse = 20.2 kJ (b) What is (triangle symbol)Hrxn when 2.3 mol S8 reacts? ∆Hrxn = (2.3*8)*(-20.2 kJ) (c) What is (triangle symbol)Hrxn when 22.8 g S8 reacts? ∆Hrxn = (22.8/(molar mass of S))*(-20.2 kJ) Please do the simple math.
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Plz help me finish my chemistry lab and plz do cuz i need them by tommorow plz help! i need a chemistry expert
** plz help i got only number 1 and 3! so plz help and if u arent going to help me then dont post anything here! DATA: 1. Mass of crucible, lid and unknown hydrate=28.26 2. Mass of crucible, and lid=25.18 3. Mass of crucible, lid and anhydrous salt =27.65 CALCULATIONS: Calculate the number of grams of water removed from the hydrate. Calculate the percent of water in the sample based on the number of grams of water removed. Identify your hydrate from the known hydrate chart. Calculate the number of moles of water removed from hydrate. Calculate the number of moles of anhydrous salt prepared. Molar Mass of anhydrous salt # 1 = 159.6 Molar Mass of anhydrous salt # 2 = 120.3 Molar Mass of anhydrous salt # 3 = 208.3 Calculate the moles of water per mole of anhydrous salt. ( #4 / #5 ) Write your experimental empirical formula for the hydrate ( salt *_#_ H2O ) Calculate the percent yield of the water driven off in this lab. Calculate the percent error in your result for 6.