How many grams of O2 are needed to produce 1.71g of NO2?
Balanced equation: 2 NO + O2 --> 2 NO2 x g --> 1.71g NO2 * 1 mol NO2 / 46.00554g NO2 * 1 mol O2 / 2 mol NO2 * 2(15.9994g) O2 / 1 mol O2 = 0.5946886831g O2 0.595g O2 (answer in 3 significant figures)
How many grams of O2 are needed to produce 1.31g of NO2?
convert the 1.31g of NO2 to moles 2 moles of NO2 are produced for every 1 mole of O2 so divide the moles of NO2 by 2 in order to change into O2 now convert the moles you now have of O2 into grams.
What is the total numbet of grams of O2 needed to produce 54 grams of water? ?
what is 02 i thought it was 2 parts hydrogen.
How many number of moles are present in 3.6gram of water (H2O)?
As we know,Mole = weight in gram / molar massHere, weight = 3.6 gmMolar mass (H2O) = (2*1)+16 = 18By putting the values..Moles = 3.6/18 = 0.2Therefore 0.2 mole are present in 3.6 gms of H20.Hope it will help you..Thanks..:-)
Chemistry question number 4?
At 75◦, the vapor pressure of water, methanol, diethylether and benzene are 289, 1126, 2680, and 644 torr, respectively. Which of these is NOT above its boiling point at normal atmo- spheric pressure? 1. methanol, diethylether, and benzene 2. None of these 3. water and benzene 4. methanol and diethylether 5. diethylether 6. water
How many grams of O2 are needed to produce 1.31g of NO2?
from your equation if the oxidation of NO, we can determine that 32 gms of oxygen yields 2*39 gms of NO2 39 gms is the molar mass of 1 molecule of NO2 and since there are 2 molecules so we multiply it with 2. from here we can calculate as below :- 32 gms of O2 yields ------------------> 2*39 gms of NO2 So,1.31gms will yield ----------------> 2*39/1.31 gms of NO2 ----------------> 3.19 gms of NO2 n nw the second part of your question How many grams of O2 are required to produce 1.31 gm of NO2 simply reverse the equation we have used above in the unitary method 2*39 gms of NO2 requires ---------------> 32 gm of O2 1.31 gm of NO2 will require ------------->( 32/2*39)* 1.31 --------------> 0.537 gm
What is the total number of grams of N2(g) in the airbag?
multiply the density by the volume
How do I calculate the amount of water produced by the combustion of 16 g of methane?
To solve such questions you must write a balanced reaction first.CH4 (g)+2O2 (g)————-> CO2 (g) +2H2O (g)Now according to the reaction 1 mole of CH4 gives 2 moles of H2OAnd 16 grams of Methane mean 1 mole (moles=given mass/molecular mass. Molecular mass of methane is 16)so 1 mole of methane = 16/16 (given mass 16 and molecular mass 16)since 1 mole of methane is getting used up to form 2 mole of water.number of moles=given mass/molecular mass ——- eq. 1molecular mass of water is 18.2=x/18 ( where x is the mass of water produced , using equation 1)2*18=36gramsso 36 grams of water will be produced.
Help With Chemistry Question 61?
On a warm day, an amusement park balloon is filled with 47.8 g He. The temperature is 33 degrees Celsius and the pressure in the balloon is 2.25 atm. calculate the volume of the balloon.