Determine the average rate of change of B from t=0 s to t=362 s.?
rate1 = (0.67 - 0.43) / 181s = 1.32x10^-3M/s rate2 = (0.43 - 0.19) / (362 - 181) = 1.32x10^-3M/s average rate = 1.32x10^-3M/s
Average Rate of Change?
In 1990, 16.2% of households had a home computer, while 66.8% of households had a home computer in 2003. Determine the average rate of change of the % of households that had a home computer over this time period. How would I solve this? Using y2-y1/x2-x1? In the back it says 3.89% / year. Everything I've tried hasn't come up with this answer.. HELP!
Determine the average rate of change of the function between the given values of the variable.?
A function is given. Determine the average rate of change of the function between the given values of the variable. f(x) = 7x − 6; x = 2, x = 3 A function is given. Determine the average rate of change of the function between the given values of the variable. h(t) = t2 + 4t; t = −1, t = 2 A function is given. Determine the average rate of change of the function between the given values of the variable. f(x) = x3 − 4x2; x = 0, x = 10
How do I find the average rate of change?
The average rate is:[math]\qquad\qquad\qquad\qquad\qquad\displaystyle\frac{\Delta y }{\Delta x} = \frac{24}{6} = 4[/math]In general:[math]\qquad\qquad\qquad\qquad\qquad\displaystyle\frac{\Delta y }{\Delta x} = \frac{f(b) - f(a)}{b - a}[/math]The formula you mentioned was correct, you probably made a simple arithmetic error.
To determine the average rate of travel between sets of travel data, why can you not divide the distance by the average time, context in comment?
OK, let’s do the math.Basic formula, of course is [math]r = \frac{d}{t}[/math].Now we’ve got two sets of measurement over the same distance and we want the average. Which would be[math]r_{avg} = \frac{\frac{d}{t_1} + \frac{d}{t_2}}{2}[/math]or[math]\frac{dt_1 + dt_2}{2t_1{t_2}}[/math]or[math]d\frac{t_1 + t_2}{2t_1{t_2}}[/math]So you can see that’s not at all the same as[math]d\frac{t_1 + t_2}{2}[/math]Which is what you’d get if you just averaged the speeds.The only reason it’s close in your case is that the numbers happen to work out that way. If instead of 9 and 11, the numbers had been 5 and 15, the right answer would be 82.67 and the “average the time” answer would be 62.
How do you find an average rate of change in a parabola?
You can start with the typical approach to finding slope for a line: start with points you know satisfy the equation (pick a value of x and solve for y, and do this for 3 points. Using two of these points x1, y1) and (x2, y2), the slope is (y2 - y1)/(x2 - x1). Then do the same calculation for (x2, y2) and (x3, y3). Slope is (y3 - y2)/(x3 - x2). Take these two slopes that you calculated and take the average of the two.
Average rate of change of the function between x = -2 and x = -2 + h?
Hi The average rate of change is given by [g(x_2) - g(x_1)]/(x_2 - x_1). Here, we have x_1 = -2, x_2 = -2 + h, and g(x) = 4/x, so we get: Average rate of change = [g(x_2) - g(x_1)]/(x_2 - x_1) = [4/(-2 + h) - 4/(-2)]/[(-2 + h) - (-2)] = [4/(-2 + h) + 4/2]/(-2 + h + 2) = [4/(-2 + h) + 2]/h To simplfiy this, we combine fractions in the numerator: [4/(-2 + h) + 2]/h = [4/(-2 + h) + 2(-2 + h)/(-2 + h)]/h = {[4 + 2(-2 + h)]/(-2 + h)]}/h = [(4 - 4 + 2h)/(-2 + h)]/h = [2h/(-2 + h)]/h = 2/(-2 + h) So the average rate of change of g(x) = 4/x between x = -2 and x = -2 + h is 2/(-2 + h). I hope this helps!