Did i solve this problem correctly? 5/1 - 1/2y?
The LCD IS 2y so you need to multiply BOTH terms in the first fraction by 2y, giving 10y/2y -1/2y which is 10y - 1 OVER .... 2y That's it ... 1 won't divide into anything, so you can't cancel the numerator terms, so just stop.
Did I solve this correctly?
X has to be 200 because the mean is adding the numbers together and dividing by how many there are so your answer can't be correct. You should have said 10+20+30+40+x/5=60 100+x/5=60 then if you were to solve the equation you would say 100+x=60*5 100+x=300 x=300-100 x=200 Hope that helps
Did I solve this problem correctly?
Yap. correct!
Did I solve this correctly?
Did I solve this problem correctly using this exact method? A small community college employs 58 full time faculty members. To gain the faculty’s opinions about upcoming contract negotiations, the president of the faculty union wishes to obtain a simple random sample that will consist of 5 faculty members. She numbers the faculty 1 to 58. Using Table I from Appendix A, the president of the faculty union closes her eyes and drops her ink pen on the table. It points to the digits in row 19, column 7. Using this position as the starting point and proceeding downward, determine the numbers for the 5 faculty members included in the sample. Member 1: 13 Member 2: 52 Member 3: 40 Member 4: 56 Member 5: 18 Heres a link to info about the problem http://media.pearsoncmg.com/ph/esm/esm_sullivan_sst3e_10/ebook/sst3e_flash_main.html?page=1 pages 31 and 32 have the information on the problem
Parabolas - did I solve this correctly?
No, you at the instant are not splendid. y = x² - 4x + 10 a = a million, b = -4, c = 10 h = -b / 2a h = -(-4) / 2(a million) h = 4 / 2 h = 2 ok = x² - 4x + 10 ok = 2² - 4(2) + 10 ok = 4 - 8 + 10 ok = 6 answer: The vertex is at (2, 6). ~~~~~~~~~~~~~~~~~~~~~~~~~ you additionally can see this by using putting it into vertex variety. y = x² - 4x + 10 team. y = (x² - 4x) + 10 element y = (x² - 4x) + 10 upload placeholders. y = (x² - 4x + ___) + 10 - a million(___) word that the 2nd sparkling is bigger by using -a million to account for what you had to function to end the sq.. Take the coefficient of the x term: -4 Divide it by using 2: -4 / 2 = -2 sq. it: (-2)² = 4 upload 4 to the two blanks. y = (x² - 4x + 4) + 10 - a million(4) x² - 4x + 4 is the better variety of a suitable sq. binomial. undergo in techniques that (a - b)² = a² - 2ab + b². word this to what you have. y = (x² - 4x + 4) + 10 - a million(4) y = (x - 2)² + 10 - a million(4) Simplify something. y = (x - 2)² + 10 - 4 y = (x - 2)² + 6 y = (x - 2)² + 6 is the vertex variety. this means: h = 2, ok = 6 answer: The vertex is at (2, 6). ~~~~~~~~~~~~~~~~~~~~~ you additionally can discover the vertex by using discover the 1st derivative. y = x² - 4x + 10 discover the 1st derivative. y' = (2)x^(2 - a million) - 4(a million)x^(a million - a million) + 0 y' = 2x^a million - 4x^0 y' = 2x - 4(a million) y' = 2x - 4 Set it to 0. 2x - 4 = 0 upload 4 to the two factors. 2x - 4 + 4 = 0 + 4 2x = 4 Divide the two factors by using 2. 2x / 2 = 4 / 2 x = 2 that's the h fee of vertex (h, ok). x = 2 = h Plug this back into the unique equation to discover the ok coordinate of the vertex. ok = x² - 4x + 10 ok = 2² - 4(2) + 10 ok = 4 - 8 + 10 ok = 6 answer: The vertex is at (2, 6).
Did I solve these problems correctly?
I did the very very best I could but I'm not sure if they're correct: 1. 5x-[2x-(3x+2)] 5x-[2x-3x-2] 5x-2x+3x+2 =6x+2 2. 8x-{2x-3[(x-4)-(x+2)]} [x-4-x-2] -3[-6] 8x-{2x+18} 8x-2x-18 6x-18 =6x-18 3. [11(a-3)+12a]- {6[4(3b-7)-(9b+10)]+11} [11a+33+12a]- {6[12b+28-9b-10]+11} [23a+33- {6 3b+28-10+11} 23a+33 {39-10} 4. -3[9(x-4)+5x]-8{3[5(3y+4)]-12} -3[9x-24+5x]-8{3[15y-20]-12} -3[24x]-8{[35y-60]-12} I got very stuck on the last 2. please and thank you in advance :)
Did I solve this equation correctly?
yet another equals become extra. that's the errors, to no longer point out the random including of a six next to the 2nd x. (x + 2)(x - 3) = x^2 - x - 6 x^2 - x - 6 - 6 = 0 x^2 - x - 12 = 0 (x + 3)(x - 4)
No. Your answer is wrong.Diagonals of parallogram are not perpendicular to each other. They bisect each other.So first find coordinates of B and D by solving equations of diagonal and side simultaneously.Then find midpoint of BD.Then the required equation is origin and the midpoint.Sorry for not providing the exact answer. Because by solving it yourself will make you perfect at this problem.
Yes it's correct, assuming the table is round.This is one of those questions that's much easier to check than it is to solve, so it looks like you've already done the hard part in giving the answer. However, there are some assumptions you made that might give different possible solutions if you assume something different. In this case, imagine the table is more like a picnic table, with two people on each side. Then we get the following:_ _===_ _Andre sits on Charmeil's left, so we have two possibilities (excluding symmetry):C A===_ _A _===C _The second possibility doesn't work with the last statement, since Duclos would be in the same seat as Andre, so we can get rid of it immediately. This leaves us with the first option, and we can put Duclos across from Charmeil, leaving Berton in the last seat:C A===D BFinally, their jobs are as follows:Andre - Butcher (from first sentence)Duclos - Grocer (from second last sentence)Berton - Baker or TobacconistCharmeil - Baker or TobacconistSo there are then two more solutions, with the same seating arrangement, but with Berton and Charmeil swapping jobs.
Well, your thought started right. All your mistakes were fool stuff.You found that [math]g(0) > f(0)[/math], which means your integral should be [math] \displaystyle\int_a^b\ g(x) - f(x) dx,[/math]. But take a look at this:[math] - \displaystyle \int_a^b\ f(x) - g(x) dx = \displaystyle\int_a^b g(x) - f(x) dx[/math]Being so, if the rest of your calculations were correct, all you'd have to do would be to multiply your result by [math]-1[/math].But, unfortunately, that was not the case. In the process of subtracting [math]f(x)[/math] and [math]g(x)[/math], you simplified the function (which should be [math]6x^2 + 6x - 12[/math]) to [math]x^2 + x - 2[/math] dividing it all by six. Notice that it changes the actual result of the integral (I know perfectly that feel. I also always want to simplify everything and eventually get into these situations.) You could have factored out the six from the integral, and it would look like this:[math]6 \displaystyle\int_{-2}^1\ (x^2 + x - 2) dx[/math]I'll repeat the calculations from that point:[math]6 \displaystyle\int_{-2}^1\ (x^2 + x - 2) dx[/math][math]6 [x^3/3 + x^2/2 - 2x] [/math] (from -2 to 1)[math]2x^3 + 3x^2 - 12x [/math] (from -2 to 1)[math]2(1)^3 + 3(1)^2 - 12(1) - [2(-2)^3 + 3(-2)^2 - 12(-2)][/math][math]2 + 3 - 12 - [-16 + 12 + 24][/math][math]-7 - [-4 + 24][/math][math]-7 - 20[/math][math]-27[/math]That's the result when calculating with [math]f(x) - g(x)[/math], but, in order to reach the correct result, it's necessary to multiply by -1, then the area between the functions is equal to [math]27[/math]A short advice: You seem to be making the calculations way too fast, I really recommend you to check all the steps you make. I used to make many operations in my mind and ended up making lots of fool mistakes, pretty much like yours, but they don't actually mean you don't know the subject, in fact, it seems you understand the theory pretty well.P.S.: I'm still getting used to formatting math text