What mass of NaN3(s) must be reacted to inflate an air bag to 69.5 L at STP?
Air bags are activated when a severe impact causes a steel ball to compress a spring and electrically ignite a detonator cap. This causes sodium azide (NaN3) to decompose explosively according to the following reaction. 2 NaN3(s) 2 Na(s) + 3 N2(g) What mass of NaN3(s) must be reacted to inflate an air bag to 69.5 L at STP?
Chemistry question... please explain?
Air bags are activated when a severe impact causes a steel ball to compress a spring and electrically ignite a detonator cap. This action causes sodium azide, NaN3, to decompose explosively according to the following reaction: 2 NaN3(s) → 2 Na(s) + 3 N2(g) What mass of NaN3(s) must be reacted to inflate an air bag to 70.0 L at STP?
Air bags are activated when a severe impact causes a steel ball to compress a spring and electrically ignite?
Okay, you have a volume, a temperature and a pressure (from STP: 1 atm, 273 K). You have everything you need but a number of moles; solve for the number of moles: PV = nRT; n = PV/RT = (1 atm)(53.9 L)/(.08206*273) = 2.406 mol (I'm using extra sig figs for accuracy's sake) Now, convert your moles into a number of grams: 2.406 mol * (65.011 g/mol) = 156 g I hope this helped!
What mass of NaN^3 (s) must be reacted to inflate an airbag of 70.0 L at STP?
^ means subscript. Air bags are activated when a severe impact causes a steel ball to compress a spring and electrically ignite a detonator cap. this causes sodium azide (NaN^3) to decompose explosively according to the following reaction: 2 NaN^3 (s) ---> 2 Na (s) + 3 N^2 (g) What mass of NaN^3 (s) must be reacted to inflate an air bag to 70.0 L at STP? Please help... I need to do better in Chemistry or my grade is in jeopardy this semester :'(
Why does air support fire when nitrogen (which extinguishes fire) is a constituent of it?
So let’s throw some numbers on here. Let’s use a nominal Oxygen concentration of 20.9% and Nitrogen of 78%. Most of the rest is argon and then a bunch of other gases under 0.1% each.You can start a fire with an oxygen concentration even below 15%. And once started it will continue to burn until around 12%. So if you’re going to use Nitrogen, or any other inert gas, you have to inject enough nitrogen to displace oxygen down to that level. Of course that means the fire has to be in a relatively tight enclosure, otherwise the natural flow of air will just keep on feeding it more oxygen.Believe it or not, you can still breathe at an oxygen concentration of 12%. Even down a little lower, but only for a short period of time. But you do have to keep in mind that a higher concentration of nitrogen is not going to be the only bad thing in the room. There will also be smoke and likely other chemical constituents from whatever was burning, possibly some of them harmful.There are regulations for all of this, including Nitrogen and Oxygen concentration levels, hazard types, alarms for personnel, etc., that most local building codes require when in use. There are also adjustments that need to be made to the calculations depending on altitude, temperature, enclosure integrity and other factors.Edit: Thank you James Pearson for pointing out my error with reference to varying Oxygen concentration by altitude. I revised my answer to delete that error and add comments about other adjustments and considerations.
Assume that an exhaled breath of air consists of 74.7% N2, 15.4% O2, 3.5% CO2, and 6.4% water vapor. PLEASE!!!?
as an answer to your e-mail: 3.5% of 455 mL = 15.925 ml of CO2 15.925 ml = 0.015925 litres 37 C + 273 = 310 Kelvin email me back, if the pressure was anything other than 1 atm PV = nRT (1 atm)(0.015925L) = n (0.08206 atm-L/mol-K)(310 Kelvin) n = 0.00062602 moles of CO2 your "3.5% had only 2 sig figs your answer, rounded to 2 sig figs would be 0.00063 moles of CO2 ======================================... by the equation: 1C6H12O6 + 6O2 -> 6CO2 + 6H2O 0.000626 mol CO2 is produced from 1/6 th as many moles C6H12O6 = 0.0001043 mol C6H12O6 using molar mass: 0.0001043 mol C6H12O6 @ 180.16 g/mol = 0.0188 grams of glucose again , you are likely expected to round off to 2 sig figs in which case your answer is 0.019 grams of glucose good luck
How does an engine start in an aeroplane?
A very very good question.Before starting, we should know, what is an APU. Also known as auxiliary power unit, it provides the aircraft with hydraulic, electric, pneumatic power when the main engines are off and compressed hot air (bleed air) to start the main engines.Theory—The compressed air which comes from the APU, is directed to an air starter unit of the engine which spins the high pressure shaft of the engine. When the high pressure shaft reaches some percentage of its maximum rpm, the fuel is injected into the engine, the ignitors inside the engine fires a spark to ignite the fuel and there the engine starts. The fuel shouldn't be injected when the shaft has not reached a suitable rpm.If we try to do so, the fuel will be vigorously ignited which will overheat the engine turbines and will damage the engine. This is known as Hot start.Engine starting procedure—Switch on the ignitors of the engine by moving the knob from Normal to Ignition mode. It is also known as the engine mode selector. It will activate the ignitors of the selected engine.This action also opens the air starter valve and the the compressed air from the APU to the air starter unit. This spins the high pressure shaft.These all actions are monitored by the pilot in the ECAM (Electronic Centralized Aircraft Monitor) display. When the high pressure shaft reaches 25% of its maximum rpm, the engine master switch is moved from Off to On. This action injects fuel into the engine and the igniters fire up to ignite the fuel.The speed of the engine increases and and the air starter unit disconnects. The engine continues to speed up and finally self sustains.The engine mode selector is turned to Normal .In the same way the second engine is started. It can also be started by crossbleed system. It is a system where bleed air from the running engine is used to start the other engines.The engine master switch is located behind the thrust levers.The buttons marked with Eng 1 and Eng 2, are engine masters. The white button in the centre is the engine mode selector.There is one engine mode selector for all engines of Airbus aircrafts.There is one engine mode selector for one engine in Boeing and other aircrafts.Hope you got your answer. Thanks a lot for asking this question to me.