How do I calculate number of bricks and cement required for a room ?
Suppose your room measurement is 3m x 5m and there is a door of 1m x 2m and the height of the room is 3m and the thickness of the wall is 23 cm.Then centre line length of this room will be 2[3.23+5.23]=16.92 mvolume of brickwork is 16.92 x 0.23 x 3=11.67cumdeduct for door [1] x 1.0 x0.23 x 2= 0.46cumdeduct for lintel over door [1] 1.3 x 0.23 x 0.1=0.03cumnet brickwork volume is 11.67- [0.46+.03]=11.18cumSuppose you are laying this brickwork in cement mortar 1:5[one of cement and five of river sand] using second class ground moulded chamber burnt bricks of size 9″ x 4 3/8′ x 2 3/8″’ then for one cum of brickmasonry, you require 460nos of bricks; 0.25 cum of river sand; 0.05 cum of cement. Since one cum of cement weighs 1440 kg, for 0.05cum , you require 72kgwe found the net volume of brickwork as 11.18cumHence number of bricke required is 11.18x460=5143nos; river sand required is 11.18 x 0.25=2.795cum; cement required is 11.18x 72=805kg