Stuck on a physics an easy question?
You'll need to use the equation q=cm(Ta-Tb). q is the heat absorbed. c is the specific heat capacity, which you'll have to look up for each material (try the back of your textbook). m is the mass of the material. Ta is the final temperature, and Tb is the initial temperature. If you get a negative number, heat was lost rather than absorbed. Good luck! (be sure to convert your units properly; grams and kilograms can get tricky.)
Stuck on a physics question?
The car's initial velocity is 50m/s. It goes from 50m/s to 0m/s in 5s. You should able to figure out the average acceleration (-10m/s^2). We have the car's initial velocity and acceleration. Use the position kinematic equations. You can use either Vf^2 = Vi^2 + 2a(ΔX) OR Xf = Xi + Vi*t + .5a*t^2 I'd probably use the first one since you don't need to deal with time. We know the car comes to a stop, so its Vf = 0 m/s. We found the a, so let's solve for ΔX: ΔX = (Vf^2 - Vi^2) / (2a) Now plug in: ΔX = (0 - (50m/s)^2) / (2(-10m/s^2) = (-2500m^2/s^2) / (-20m/s^2)....... Note the unit cancellation = 125m This is the CHANGE in X, aka the distance it took to go from Vi to Vf in velocity. Average force = impulse / time Ok, we have the mass and Vi of the car. We know that its initial momentum = 700kg*50m/s = 35000Ns Its final momentum = 700kg * 0m/s = 0Ns So the impulse (change in momentum) = 35000Ns So the average force is 35000Ns/5s = 7000N. In summary 1) Find average accel 2) Find distance travelled using that accel, initial velocity, and time depending on the kinematic equation. 3) Fave = impulse / time
Help with physics question I'm stuck on?
Energy to lift train = mgh = (9750kg)(9.8m/s^2)(53.3m) = 5.093 * 10^6 J Im pretty sure the time doesnt matter...work is just force * distance...so the work done in 5.093 * 10^6 Joules Now if you want the power the train takes that is P = E/t = 5.093 * 10^6 Joules/18.55secs = 94,472 kW
Stuck on this Physics Question?
Equate elastic potential energy to kinetic energy. 1/2 kx^2 = 1/2 mv^2 Cancel 1/2 kx^2 = mv^2 V is what you're looking for: kx^2 / m = v^2 v = sqrt (kx^2 / m) v = sqrt (78 Nm (0.02 m)^2 / 0.085 kg) v = 0.6059 m / s
Physics Question?
Your car is stuck in a mud hole. You are alone, but you have a long, strong rope. Having studied physics, you tie the rope tautly to a telephone pole and pull on it sideways at the midpoint, as shown. 386 N 3.4◦ 12m A)Find the force exerted by the rope on the car when the angle is 3.4◦ and you are pulling with a force of 386 N but the car does not move. Answer in units of kN. B)How strong must the rope be if it takes a force of 601 N to move the car when θ is 3.3◦? Answer in units of kN.
Physics question . stuck on these questions .. help?
In both of these problems, the final momentum is equal to the initial momentum. 1. A cannon of mass 750 kg mounted on a level track fires a 5.0 kg projectile with a speed of 250 m/s at 300 up from the horizontal. What is the recoil speed of the cannon? Initial momentum = 5 * 250 * cos 30 = 3,125 * √3 Final momentum = 750 * v 750 * v = 3,125 * √3 v = 3,125 * √3 ÷ 750 The recoil speed is approximately 7.2 m/s. 2. A stunt man of mass 100 kg drops into a cart of mass 500 kg rolling on a level track at 10 m/s. What is the speed of the cart after the stunt man drops into it Initial momentum = 500 * 10 = 5,000 kg * m/s Total mass = 600 kg Final momentum = 600 * v 600 * v = 5,000 v = 5,000 ÷ 600 = 8⅓ m/s
I am currently stuck on this physics question. if any of you lovely intellectuals could take a crack at it, i would greatly appreciate is.?
You can approach this in two ways. It is based on the moment of inertia. One way is to know that a solid cylinder acts, at its peripery, as a mass of 1/2 of the mass of the object. v = 360 * 2*pi() * 0.5 / 60 F = ma so a = 34 / ( 20/2) t = v/a Alternatively you find the angular momentum of the object i = 1/2 m r^2 then the angular velocity of the object w = 2 * pi() * 360/60 and the torque = 34* 0.5 time = w/ ( angular acceleration) = w / ( torque/ moment of inertia) If you write the two methods out with all values you discover that there are quite identical. Which naturally they must be because they are descriptions of the same problem.
Physics problem are not difficult but the thinking process involved is difficult to develop and that can be achieved by practicing problems daily.Now how do you go about solving numericals:-1. Read the problem line by line. NEVER read the full problem at a go.2. Write down the data in your copy and see what has to be found. Look for hidden information like "A concave lens has a focal length of 10cm"So you should know that concave lens has negative focal length and use -10 cm instead of 10 cm.3. Now that you have written everything down remember formulae that can be used to solve the problem. Most important thing is that you have all your concepts clear in mind. Try deriving the formulae which have been derived. Read the solved examples of your text and see how they have been solved because most of the exercise questions can solved in a similar manner.If you don't get some problems don't get depressed because you may get doubts in some concepts and make sure to clarify them. If you don't get a problem at once don't run to anyone to get it clarified, leave that problem for that time and try it again the next day because your teacher may cover that concept the next day or you may read it somewhere. Read a book which you can understand easily.. In my opinion Modern abc is a good book as it starts from basics.Thanks for reading.
In the case first solve all the easy question in order to gain enough confidence to grab the hard one. In physics some questions seem hard and lengthy but instead they are tricky ones,so you better try to solve the question again and again with different approach. If a question is taking too much time then you are possibly doing it wrong.Then discuss the question with the teacher. If he also verify that question is too long then the best option is LEAVE IT. As in JEE paper most of the questions are trickier one not the lengthy one(generally). I would recommend you to do more of the questions which uses your brain rather then your time.
No not at all. In my opinion I wouldn't hesitate from calling it easy. NEET physics is at a pretty basic level.Sadly most medical aspirants hate physics and tend to neglect it thinking that they would compensate in biology and chemistry. The end result is that their ranks take a huge blow. Let me tell you that physics will be the deciding factor of your NEET rank.Now coming to how to prepare for it? Most aspirants make a mistake of referring to too many books for Physics which are beyond the scope of NEET syllabus. My advice is that you stick to your NCERT syllabus. Always refer NCERT first for your concept building. After going through a concept immediately go through mcqs related to that topic given in your coaching centre material, mock exams and past papers. Pay particular attention to numerical based problems as this is where many students fail. Physics requires extensive practice to perfect so go through all kinds of mcqs related to NCERT concepts. If you practice well enough then you will surely be satisfied with your physics performance. Believe me NEET physics is a cakewalk if you practice the right way.