What do you do when you don't know how to solve a math problem?
If its your maths homework, then the solution probably relies on something you did in class earlier - try to relate that to the problem.If you know what you need to apply but can’t solve the problem, try to get a hand hold on it so you can ask pertinent questions. Look for a similar problem on the internet perhaps or in textbooks.Draw a picture - if that makes any sense - often that will give you new clues to work with.Try to read several different books / web articles on the material you are working on, they may cover that problem in a bit more detail.Don’t give up - you don’t get good at maths without a bit of pain, but the struggle with solving a problem will help you understand and move on to a higher level. Its ok to talk to your professor or fellow student, but don’t let them give you the entire solution, a tip or clue is good, but do your own working. And make sure you understand the clue, don’t just accept it blindly, your fellow student may just be wrong and not know what he’s talking about.
Algebra questions, need help?
1. 2x+17=55 -- Subtract 17 from both sides. So then it's.... 2x=38 Then divide each side by 2x x=19 Makes sense because if you do fill in the 'x' 2(19)+17=55 3. -(x-3)-2(x-4)=7 I like to change it to addition -1(x+-3)+-2(x+-4)=7 Remember, if theres no number next to the parenthesis it's a 1. Distribute the 1 and the 2. -1x+3+-2x+8=7 Add like terms -3x+11=7 Subtract 11 to both sides. -3x=-4 Divide each side by -3x x=4/3 I think. I'm not sure about this one. Hope I helped.
Riemann Sums and Integration help?
A partition is a decomposition of the interval in question into smaller 'subintervals'. The given partition P divides [0, π/2] into thee four subintervals [0, π/6], [π/6, π/4], [π/4, π/3], [π/3, π/2]. With each of these, we use rectangles to approximate the area under the ciurve. Note that f(x) = sin x is increasing on (0, π/2). So, for each subinterval, the minima occur at the left endpoints, while the maxima occur at the right endpoints. Hence, L(P) = sin(0) (π/6 - 0) + sin(π/6) (π/4 - π/6) + sin(π/4) (π/3 - π/4) + sin(π/3) (π/2 - π/3) .......= 0 (π/6 - 0) + (1/2) (π/4 - π/6) + (√2/2) (π/3 - π/4) + (√3/2) (π/2 - π/3) .......≈ 0.769 U(P) = sin(π/6) (π/6 - 0) + sin(π/4) (π/4 - π/6) + sin(π/4) (π/3 - π/4) + sin(π/2) (π/2 - π/3) .......= (1/2) (π/6 - 0) + (√2/2) (π/4 - π/6) + (√3/2) (π/3 - π/4) + (1) (π/2 - π/3) .......≈ 1.197. I hope this helps!
Volume using Riemann Sum- Please help!?
you need to give us more information: 1. you gave us a two dimensional picture, how are you creating a volume? rotating what area around what line? 2. you need to give us the limits of integration let's say you were only doing the area between those two curves from 0 to 1, then your work would look like this: n=14; h=0.07142857142857142: Left Riemann: 1: 1 × 0.0714 = 0.0714 2: 0.9333 × 0.0714 = 0.0667 3: 0.8746 × 0.0714 = 0.0625 4: 0.8218 × 0.0714 = 0.0587 5: 0.7726 × 0.0714 = 0.0552 6: 0.7249 × 0.0714 = 0.0518 7: 0.6764 × 0.0714 = 0.0483 8: 0.625 × 0.0714 = 0.0446 9: 0.5685 × 0.0714 = 0.0406 10: 0.5047 × 0.0714 = 0.0361 11: 0.4315 × 0.0714 = 0.0308 12: 0.3466 × 0.0714 = 0.0248 13: 0.2478 × 0.0714 = 0.0177 14: 0.133 × 0.0714 = 0.0095 Total: 0.6186224489795918
What is the sum of the numbers from 1 to 20?
The fastest way to calculate isn/2(a+l)n=number of terms. In this case, 20.a=the first term. 1 in this casel=last term, 20 in our case.Hence it comes to be 20/2(1+20)=10(21)=210It is a formula of Arithmetic Progression which I learnt in school.Disclaimer: The formula is applicable only when the series is of a consecutive integers.Hope it helpsFor some reason, the answer collapsed. I don't know why. It is frustrating when this happensThe answer here is for the shortest/fastest way. You can't expect me to write a 2 page answer for the same. Ironically, it prompts me to answer it better to make it 'helpful'So I would one more example. Let's say you need a sum of numbers 1 to 100So according to the formula stated above 100/2(1+100)=50(101)=5050.I hope the answer doesn't collapse now. Phew!
College Math Course Questions, Please Help!?
just try the problem out .323232323232 +.123123123123 ------------------------- .446355446355 see how the pattern is now, 446355 most problems like this could just be solved by taking the number of digits and multiplying them together, for example, .32 is 2 digits and .123 is three digits, 3x2 is 6. an easy way that is close but not right on would be to take the fraction 444/1000 and 500/1000 and find the average which is 472/1000 because the 4 was repeating, the two will also. you can check what repeats by taking a larger fraction like 444444/1000000 and 500000/1000000 which gives you 472222/1000000 hope that helps :)
Math help!! please help me!!?
1. there are none. there are two consecutive integers 10 and 9. i did the the math and i got 8.359 and 10.359 and those arent integers therefore not odd or even. 2. two consecutive negative integers could be -x and (-x-2) but it doesnt matter cuz ur finding the squares. so ur equation is x^2 + (x-2)^2 = 100 x^2 + x^2 - 2x - 2x + 4 = 100 2x^2 - 4x + 4 = 100 Now you have to do quadratic equations 2x^2 - 4x - 96 = 0 your answer comes out to be -6 and 8 but they want negatives so its -6 and -8. you can check it. 3. if you take one of the numbers and add 5, youll get the other number so these numbers can be represented as x and (x+5). once again ur adding the squares. x^2 + (x+5)^2 = 233 x^2 + x^2 + 5x +5x +25 = 233 2x^2 + 10x + 25 = 233 2x^2 + 10x - 208 = 0 Quadratic equation. Your answer is 8 and -13. but its positive so its 8 and 13. you can check that too.