Math Challenge question!! VERY Hard!!!?
ronald has x apples he sells .2x apples to mary, so then he has .8x apples remaining. He then sells .2(.8x) apples to Gregory, so then he has .64x apples remaining. He then sells .2(.64x) apples to Carolyn, so then he has .512x apples remaining. He then sells .2(.512x) apples to Joy, so then he has .4096x apples remaining. He then sells .2(.4096x) apples to Ann, so then he has .32768x apples remaining. So what this means is --- .32768x has to be a natural number, it must be divisible by 3125 because 1024/3125 = .32768. There is only 1 number less than 5000, which is divisible by 3125, and thats 3125 itself. Therefore Ronald started with 3125 apples. He gave 625 apples to Mary, and was left with 2500 apples. Then he gave 500 apples to Gregory and was left with 2000 apples. Then he gave 400 apples to Carolyn, and was left with 1600 apples. Then he gave 320 apples t Joy and was left with 1280 apples. So the answers are, 1) Ronald began with 3125 apples 2) He now has 1280 apples.
3 very difficult and challenging maths questions!!?
Here are 3 very difficult but challenging problems for all of you: 1).A recent question asked: What is the smallest value of x such that x² - 157 = y² and x² + 157 = z²? It is known that the answer can be found from the double of a rational point on the curve y² = x³ -157² x, with y not zero. Find such a rational point on the curve and show how you got it. 2. A month ago D.L. Denis asked the question: Is there an x such that x+3 and x²+3 are both cubes? Show that, in fact, there is no integer x such that x²+3 is a cube. 3. (This problem was posed to me 12 years ago.) In a normal nxn magic square(i.e., one containing all numbers from 1 to n²) the sum of each row or column is (n³+n)/2. The numbers in this sequence are called magic square constants. Is 34 the largest Fibonacci number that is also a magic square constant? Prove your answer! (For more about magic squares see http://en.wikipedia.org/wiki/Magic_const...
Challenging math questions?
Let abcd be the number with 0<= a,b,c,d <= 9 that is N = a + 10b + 100c + 1000d We have the restriction that a = 2A, b=2B, etc. with 0 <= A,B,C,D <= 4 So 3N = 6A + 60B + 600C + 6000D with A,B,C,D = 0,1,2,3,4 only. So there are a maximum of 625 possibilities. D cannot be 0 since we need 4 digit numbers. We quickly note that A = 0,1,4 since if A = 2,3 then 6A = 12 or 18 and that one will cause 3N to have an odd number since 60B cannot eliminate that 1. This reasoning applies to each digit I believe. Thus, we have 3^4 = 81 possibilities. Anyone want to double check this line of reasoning?
Hard maths question? anyone up for the challenge?
You are given that 1 tonne = 1000 kilograms and 1 kilogram = 1000 grams A skip contains half a tonne of newspapers when full Each newspaper weighs about 200 grams Approximately how many newspapers would fill the skip? How would i work this out? Must show working:') If you answer THANKYOU!
Looking for challenging math questions?
go to http://mathgod.com/mathcomps/interschools/fall2007/fall2007interschool-test.pdf and see if you can figure these out?!!! I need to do them for Mu Alpha Theta, and its not cheating cuz it says I can use any resource (see for yourself) that includes internet and other ppl!. I'm a freshman and let me tell ya, if I try these I will be going in way over my head. Computer programs help, especially for the last questions that aren't really questions, don't ask me which ones! I have no idea...I got a few answers though.
Math Problem Challenge?
I assume you want the values of x and y? Top triangle hypotenuse: sqrt( (y-4)^2 + 16 ) Top triangle vertical leg: y-4 Full triangle hypotenuse: 12 Full triangle vertical leg: y By similar triangles sqrt( (y-4)^2 + 16 ) / (y-4) = 12 / y Multiply by (y-4) and y: y sqrt( (y-4)^2 + 16 ) = 12 (y-4) Simplify: y sqrt( y^2 - 8y -16 + 16 ) = 12y - 48 y sqrt( y^2 - 8y ) = 12y - 48 y sqrt( y (y-8) ) = 12y - 48 Square both sides: y^2 * y(y-8) = (12y - 48)^2 y^4 - 8y^3 = 144y^2 - 8*144y - 48^2 y^4 - 8y^3 - 144y^2 + 8*144y + 48^2 = 0 Now just solve for y, and from there it is easy to solve for x... After a bit of playing with an Excel spreadsheet, I'm getting the following pairs: x = 6.680915, y = 9.968218 x = 9.968218, y = 6.680915 Notice how these are symetric answer depending on whether x is a long leg or y is a long leg. Double checking the answers we get: x^2 + y^2 = 12 sqrt((x-4)^2 + 4^2) + sqrt((y-4)^2 + 4^2) = 12 The two solutions are therefore: x = 6.680915, y = 9.968218 (y is the long leg) x = 9.968218, y = 6.680915 (x is the long leg) If you assume y > x, then the first solution is the only solution.
What are some creative, fun and challenging math questions?
I am sorry to say that I am not good at coming up with fun and challenging math questions for people because my perspective of “fun and challenging” in mathematics is different from how other people feel about math.However, I can suggest that instead of asking for creative, fun and challenging math questions, you can try to create some yourself by researching for some current world problems or how to apply mathematics in places that it is commonly not used.The reason I would suggest creating your own math problems is that the challenge becomes not just to solve the problem, but to create tools to get you to the answer. So many people know how to solve a given problem, but not many people know how to create a problem for themselves to reach to an answer not in the answer sheet. For example, you would use math to calculate how much fuel to put into an airplane without it stopping for a break (or crashing mid-flight). Or, you would use math in physics to predict, create designs, etc. that work smoothly. Or, you could use math in art to create tools for yourself.Math is more than just solving questions.
How do I challenge math universities to solve my questions?
Oi! Princeton! Solve this, or your willy is tiny and malformed!Something like that?Mathematicians are sometimes very fiercely competitive individuals (certainly not always), but I don't think that university departments are very responsive to “challenges” issued like demands for trial by combat.You could try asking them instead.
Math Survey for those who are up to a challenge?
Hello, I am conducting a survey for my college course on whether or not you can solve the following the problems and your evaluation overall for the questions. 1. A 100-foot wire is extended from the ground to the top of a 60-foot pole, which is perpendicular to the level ground. To the nearest degree, what is the measure of the angle that the wire makes with the ground? a. 31 b. 37 c. 53 d. 59 2. The length of the hypotenuse of a right triangle is 34 inches and the length of one of it's legs is 16 inches. What is the length, in inches, of the other leg of this right triangle a. 16 b. 18 c. 25 d. 30 3. The length of the hypotenuse of a right triangle is 20 centimeters and the length of one leg is 12 centimeters. The length of the other leg is: a. 8 cm b. 16 cm c. 32 cm d. 36 cm 4. A wire reaches from the top of a 13-meter telephone pole to a point on the ground 9 meters from the base of the pole. What is the length of the wire to the nearest tenth of a meter. a. 15.6 b. 15.8 c. 16.0 d. 16.2 5. The straight string of a kite makes an angle of elevation from the ground of 60 degrees. The length of the string is 400 feet. What is the best approximation of the height of the kite. a. 200 feet b. 250 feet c. 300 feet d. 350 feet That is all the questions. If you wish to participate in another survey for my study, please just email me.
What kind of people like it when you ask them difficult questions?
People who like a challenge. People who don’t always like a lot of competionAnd people who are lowLeval polymaths (knowledgeable about a wide area of knowledge and subjects)And people who strive to be very objective even though our spin or outside of the box crust is all too often mostly subjective in what we consider fascinatingSometimes difficult questions are my only shot at being in the limelight