TRENDING NEWS

POPULAR NEWS

Help With A Physics Problem About Wave Optics.

Help with Physics optics problems?

Hello! I'm learning about optics in Physics, and need some help figuring out these two problems.

If you could help me set it up (or even solve), that would be most appreciated!

Thank you! :)

1. A ray of light passes from air (index of refraction of 1.0) into water (index of refraction 1.33) at an angle of 30 degrees. Find the angle of refraction.

2. A converging lens (convex) has a focal length of 40 cm. If an object is placed 80 cm in front of the lens, where is the image located? Draw a ray diagram to show the orientation of the image.

Physics wave optics problem?

Let's refer to wavelength in air as λa and in glass as λg. Refraction law says λa = nλg. Note the m=12 dark fringe occurs for a phase difference of 12.5λ.
The inserted glass has increased the phase lag by 12.5λa, which causes the observed Δm=12.5 screen displacement shift.
A given shift of Δm cycles occurs over a glass thickness t when t/λg = t/λa+Δm ==>
t(λa/λg - 1) = Δmλa ==> t = Δmλa/(n-1). (general formula)
The glass thickness = 12.5*633/1 nm = 7912.5 nm.
Note I'm using small-angle assumptions everywhere. The light is assumed to travel at 90 deg through the glass, and on-screen displacement from center is assumed directly proportional to phase difference.

Physics problem - wave optics?

In a double slit experiment, the equation for fringe spacing is y= m*lambda*L/d.
y is the fringe spacing, L is the distance to the viewing screen and d is the slit spacing.

1) by submerging it in water, speed is decreased therefore the wavelength decreases. Look at eqn v = lambda*freq. So if the wavelength decreases the fringe spacing (y) decreases
2) increasing slit spacing (d): decreases fringe spacing
3) increasing the distance to viewing screen (L) : increases fringe spacing
4) Increasing wavelength: increases fringe spacing.

Need help with this physics optics problem?

focus length is - r/2 = - 3.15/2 = - 1.575 cm (negative because behind the mirror)

now use
1/f = 1/do + 1/di
1/- 1.575 = 1/24.2 + 1/di
di = - 1.478 cm = image distance (negative, because di is behind the mirror. )
the image is virtual and upright.
--
the magnification m = id di/do = (-) 1.478/ 24.2 = (-) 0.061



OG

Physics Optics Problem?

The object in the figure below is midway between the lens and the mirror. The mirror's radius of curvature is 20.0 cm, and the lens has a focal length of -17.0 cm.

1) Considering only the light that leaves the object and travels first toward the mirror, locate the final image formed by this system.
2) What is the overall magnification of the image?

http://www.flickr.com/photos/8609704@N02...

Physics : Wave optics?

In physics, physical optics, or wave optics, is the branch of optics which studies interference, diffraction, polarization, and other phenomena for which the ray approximation of geometric optics is not valid. This usage tends not to include effects such as quantum noise in optical communication, which is studied in the sub-branch of coherence theory.

Physics Optics problem?

first lens,

1/s + 1/s' = 1/f

1/30 + 1/s' = 1/25

s' = 150 cm





for the second lens,

s = d - s' = 14 - 150

s = -136 cm

1/s + 1/s' = 1/f

1/(-136) + 1/s' = 1/25

s' = 3400/161

s' = 21.118 cm







M = (s'/s)_first (s'/s)_second

M = (150/14)(3400/161)/(-136)

M = -1.66 times

negative means inverted image

Physics - Wave optics?

Please help me understand these physics problems. I have provided the answers. I just can't quiet figure out the work and which equations to use. Thank you.

Light of wavelength 700 nm is incident on a pinhole of diameter 0.1 mm.

(a) What is the angle between the central maximum and the first diffraction minimum for a Fraunhofer diffraction pattern? θ = 8.54 mrad

(b) What is the distance between the central maximum and the first diffraction minimum on a screen 8 m away? y min =L tanθ --> y min =6.83cm

(I am a student trying to understand and learn; please, no rude or sarcastic answers. Thank you.)

Physics Question, Wave Optics, HELP!?

Four trials of Young's double-slit experiment are conducted.
(a) In the first trial, blue light passes through two fine slits 400 µm apart and forms an interference pattern on a screen 4 m away.
(b) In a second trial, red light passes through the same slits and falls on the same screen.
(c) A third trial is performed with red light and the same screen, but with slits 800 µm apart.
(d) A final trial is performed with red light, slits 800 µm apart, and a screen 8 m away.

(i) Rank the trials (a) through (d) from the largest to the smallest value of the angle between the central maximum and the first-order side maximum. In your ranking, note any cases of equality. (Use only ">" or "=" symbols. Do not include any parentheses around the letters or symbols.)




(ii) Rank the same trials according to the distance between the central maximum and the first-order side maximum on the screen. (Use only ">" or "=" symbols. Do not include any parentheses around the letters or symbols.)

How do I do this physics (optic) question?

Quora is not the place where people do your homework for you - however, you have not asked anyone to do your homework, you are asking for help with your homework. You are stuck, and need a nudge.The best place to get the help you need would be Physics Forums - The Fusion of Science and CommunityMeantime, have you tried following the suggestion?You have a rule for how to find the location of the image given the position of the object … so treat one end of the rod as the object, and treat the other end as another object.

TRENDING NEWS