Help With Math Needed.

Help with math needed?

Okay, simplify it so you have 0 = ......
3000 = 16t^2 +480t +55
0 = 16t^2 + 480t + 55 - 3000
0 = 16t^2 + 480t - 2945

Then you can factorise it, or use the quadratic formula. If you use the quadratic formula, you will finish with:
1/4(-60 - SQRT 6545) = t
1/4(SQRT 6545 - 60) = t

So those are your points when y = 0

Math Help Needed!!?

Make a sketch of the situation (a graph drawing calculator might help). The curve is a parabola with the apex at y = -8.
Put a dot on the curve and label it P. join this to the point (1,0)
Draw a line straight up or down from P to the x axis. you will now have a right angled triangle on which you can do a pythogoras type calculation. The base is x - 1 and the height is y which we know is x^2 - 8. Therefore using pythagoras
d^2 = (x - 1)^2 + (x^2 - 8)^2. There is no need to multiply out the brackets. Put x = 0 into this to find the first distance and put in x = -1 for the other. I'll leave you to do this. Don't forget to square root but leave it as sqrt(something) as it's not exact.
The last part is very hard (even for me!) so I wonder whether you have copied the question correctly (I don't have the book), especially as the square roots above did not work out nicely as I would expect.

Good luck with the course. Hope that this time you succeed.

Edit. One of the above answers is wrong unless it's altered later (mainly because he multiplied out unnecessarily).
You get a lot of wrong answers on this site!

Need help with math Algebra 1?!?

1) y=x-2 then 4x+1=x-2 because you substitute the y with the 4x-2 because they are equal. then you need to get all your xs on one side. 4x-x=-2-1 they change signs (+ or -) because really you are subtracting or adding to both sides. Then you add or subtract because they are first in the order of operations. So you get 3x=-3. Then you need to get the 3x to turn into just x so divide both sides by three. x=-3. Tada! so that is X now take that information and plug it into one of the original equations. Let's do the first but it doesn't really matter. So we get y=(-3)-2. (-3) used to be x. So now simplify for y=-5. And that's it. X=-3 Y=-5

2) again let's substitute the y in the first equation with the -x+2 in the second. They are equal to each other. (It's like saying "one" and "1", it's the same thing.) So we get
-x+2=x-4. Now we need your xs on one side. I like the left. So we subtract x from both and subtract two from both also. We get -x-x=-4-2. Again they change signs. Now we need to simplify some to get -2x=-6. Now we need to divide both sides by -2 to get x all alone. x=3 So let's put that into an original equation. y=(3)-4. That turns out to be y=-1 right? So that's it. X=3 and Y=-1

3) I'll leave this one up to you. Good luck.

Math help needed desperately?

An administrator for a major hospital is trying to decide how many units of disposable bedside supplies should be ordered and held next year. The forecasting experts have said that the quarterly number of patient days for next year is 50,000 in the first quarter, 20,000 in the second quarter, 90,000 in the third quarter, and 40,000 in the last quarter. The total number of patient days for next year is forecasted to be 200,000.

Every day that a patient is hospitalized, they receive a set of pre-packaged supplies first thing in the morning or upon check-in. Regardless of use or not, the supply set is disposed and replaced the next day. Each set costs $50. The sole supplier for the product will refill an order immediately but there is a $50 fee for placing an order. One problem for the hospital is storage space. It is found that storing an item costs the hospital $6 over a year.

The administrator comes to you, his favorite fixit person. You seem to have a knack for making the right decisions. What should the hospital do? The head of nursing suggests using the Economic Order Quantity model to determine the optimal number of items to order at a time. Initially you agree, but upon contemplation you think that that model should be amended to account for the quarterly differences.

Find the Q* and total cost of the policy.

So lost. Can anyone help solve? Your help is appreciated. Thank you.

Need help with math problem?

C: -3

The elimination method has you take the two equations and manipulate them to eliminate the variable you do not need. Usually this will involve multiplying one of them by some convenient number and then adding/subtracting them (depending on that convenient number!). But, here they are already convenient (because both have 2y) so just subtract the 2nd equation from the 1st one:

(2x + 2y) - (x + 2y) = -5 - (-2) so:
2x - x + 2y -2y = -5 + 2 and:
x = -3


Added:

Everyone else is doing it by the substitution method or adding unneeded steps (why multiply by -1 and then add when you can simply subtract right away???). Or flat out getting it wrong by dropping signs, etc. That illustrates the need for keeping it as simple as you can! Less time wasted and far fewer mistakes to miss...

Help for math problems needed please?

1. Use algebra, let x = the number, therefore:

2x + 5 = 53
2x = 48
x = 24

2. Expand the brackets first

3a^4 + 3a^2 - 6a^2 - 6 then simplify
3a^4 - 3a^2 - 6 there are no more like terms, so cannot be simplified further.

3. 4a^2b^2(3-4b)

4. I used the completing the square method, as follows

x^2+12x+35

you divide the 12 by 2 to give you 6 and square that and add it into the equation as an addition and a subtraction, so it has no effect on the initial equation:

x^2 + 12x + 6^2 - 6^2 +35

If you look at the first half, it makes a perfect sqaure.

(x + 6)^2 - 36 +35

Simplify to

(x + 6)^2 -1

5. This one is easier, you can find two number that add together to make the 11 and multiply together to make 30 (coefficient of m^2 times the constant term (last number) ) which in this case are 6 and 5. Sub them into the equation in place of the 11m:

2m^2 + 6m + 5m + 15

Easier to factorise now

2m( m + 3) +5(m + 3)

(m + 3)(2m + 5)


Hope i helped!!

NEED HELP WITH MATH PROBLEM!!?

1)
A club treasurer has $28.45 consisting of nickles, dimes, and quarters. She has 9 more nickles than dimes and three times as many dimes as quarters. How many does she have of each?

Let: N = number of nickels
D = number of dimes
Q = number of quarters

Eqn1: 0.05N + 0.10D + 0.25Q = 28.45
Eqn2: N = D + 9
Eqn3: D = 3Q

Isolate Q in Eqn3:
Q = D/3 Eqn4

Substitute Eqn2 and Eqn4 in Eqn1, then solve for D:
0.05N + 0.10D + 0.25Q = 28.45
0.05(D + 9) + 0.10D + 0.25(D/3) = 28.45
Multiply each term by 3 to remove the fraction:
0.15(D + 9) + 0.30D + 0.25D = 85.35
0.15D + 1.35 + 0.30D + 0.25D = 85.35
0.15D + 0.30D + 0.25D = 85.35 - 1.35
0.70D = 84
D = 120

Substitute to Eqn2, then solve for N:
N = D + 9
N = 120 + 9
N = 129

Substitute the value of D to Eqn4, then solve for Q:
Q = 120/3
Q = 40

Check using Eqn1:
0.05N + 0.10D + 0.25Q = 28.45
0.05(129) + 0.10(120) + 0.25(40) = 28.45
6.45 + 12 + 10 = 28.45
28.45 = 28.45 Yes!

Therefore, the club treasurer has 129 nickels, 120 dimes, and 40 quarters.

2)
In a triangle, the measure of one angle is twice the measure of another angle. The third angle is equal to the sum of the other two angles. What are the measures of the angles?

Let:A = the first angle
B = the second angle
C = the third angle

Eqn1: A + B + C = 180
Eqn2: A = 2B
Eqn3: C = A + B

Substitute Eqn2 into Eqn3:
C = A + B
C = 2B + B
C = 3B Eqn4

Substitute Eqn2 and Eqn4 to Eqn1, then solve for B:
A + B + C = 180
2B + B + 3B = 180
6B = 180
B = 30

Substitute into Eqn2:
A = 2B
A = 2(30)
A = 60

Substitute the value of B to Eqn4:
C = 3B
C = 3(30)
C = 90

Check using Eqn1:
A + B + C = 180
60 + 30 + 90 = 180
180 = 180 Yes!

Therefore the angles measure 30, 60, and 90 degrees.

Math help really needed!!!!!!!!!!!!!!!!!!!!!!!!...

really? This is just simple math. Use a calculator, it will take you all of five minutes to complete.

Math grade 9 algebra help needed please!?

let the original number be xy. which means 10x + y
now equation is x+y=12

now after interchanging it is yx which means 10y + x
so the equation becomes 10x + y + 54 = 10y + x
9x - 9y = - 54

using equatin 1 and 2
x+ y =12
9x - 9y = -54


equation 1 becomes: 9(x+ y = 12) = 9x + 9y = 108

using this equation it becomes
9x + 9y = 108
9x - 9y = -54
_______________
18x = 54
x = 3



if x=3.............putting it in equation 1...it becomes x+y=12.......3+y=12........y=9
so original number was 39 and after interchanging it was 93.......perfectly 54 more than the original number........hope it helped