Help with a Math word Problem?
Mrs. Jones returned to college to finish her degree. She must have an average of 85% for her employer to reimburse 85% of the tuition fees. She has scored 84,75,87,96, and 75 on her exams. All exams scores are given in percents. If Mrs.Jones can earn a 90%, her employer will reimburse 90% of her tuition fees. If her professor uses the mean, can Mrs. Jones score enough points to receive a 90% average on six exams? If not, what is her highest possible average? Round to the nearest tenth. Please explain how you figure out the answer.
Help with a math word problem?
(750 + 225) / 15 = 65
Help with a math word problem?????
Hi, Just set up a proportion: height of fence......height of flagpole ---------------------.=.--------------... fence shadow........flagpole shadow 3........x ----.=.---- 4........72 Now cross multiply and solve! 4x = 3(72) 4x = 216 x = 54 I hope that helps!! :-)
Math word problem help?
When working with scales, 1:20 works for single dimensions (i.e. length or width) (1:20)^2 works for two-dimensions (i.e. area) (1:20^3 works for three-dimensions (i.e. volume) 1) (1 / 20)^2 = x / 300 1 / 400 = x / 300 300 / 400 = x 0.75 = x 2) 0.75 m^2 = (0.75 m^2)(100^2 cm^2 / 1 m^2) = (0.75)(100)^2 cm^2 = 7500 cm^2
Math word problem help please?
If Gino invested x dollars at 7%, then he had 10000 - x to invest at 6%. Simple interest is i = prt, so, in this case, i = 7% * x * 1year + (10000 -x)*6% * 1 year: 600 = 0.07x + 0.06*(10000 - x) 600 = 0.07x + 600 - 0.06x 600 - 600 = 0.07x - 0.06x 0 = 0.01x 0 = x So, Gino didn't invest any money at 7% and invested the entire $10,000 at 6%.
Help with this math word problem?
so it's 44% beacause if only 2/5 voted for ms smith that would mean that the rest voted for mr johnson so yeah mr johnsons group is bigger because 5-2=3 and 3>2
I need help with a math word problem?
Suppose you work for a large coffee distributor that has a secret coffee blend it sells to local stores. You mix the Ethiopian blend with the Gualtemala Antigua blend, but always in the same proportion. Yesterday, you mixed 100 pounds of the Ethiopian blend with 60 pounds of the Gualtemala Antigua blend. Today, there is 60 pounds of the Ethiopian coffee left in stock. How many pounds of the Gualtemala Antigua coffee should you mix with it to get your secret blend? Answer:_______pounds
Where can I find help with word problems in math?
Hello, I was a Maths faculty for competitive exams. I have come across many students who find word problems difficult. If you are one of them, then please do not worry because you are not alone. Let us understand first why we find Maths word problems difficult.We focus on steps and calculations with perfection but in that process, approach towards the problem gets ignored. See the following example.If I ask you, what is LCM of 45, 55, 65, you will tell me within few seconds. If I ask you another question, what is least 4 digit number, within one second you will answer me and you will look at me with surprise that why am I asking you such basic questions.Now if I ask you which is the least 4 digit number that is divisible by 45, 55, 65 ? Now you get stuck. Here also you need to use the concept of LCM only and use the fact the least 4 digit number is 1000. If you follow these two concepts, only then you will be able to solve this example. But we are so engrossed in steps of LCM, that we ignore the core meaning and implication of LCM.Many competitive exams taste your concepts and hence solving word problems is very important.What we can do is, when we read a problem, first just read and understand the given data. Then think, what other entities we can find using this given data. And then go to the last line of problem where actual question is mentioned. When you practice in this manner, gradually you will start reading examiner’s mind. Why he has asked this question? What skill he wants to check?That way your brain will start understanding the approach as soon as you start reading a problem and then whole problem is clear in your mind till you reach the last line.If you need any additional help, you can watch my videos. Out of passion of teaching, I have launched my channel which is absolutely free.I have covered all basics first to help fast calculations orally without calculator. In every chapter, I first explain all fundamentals and then also the shortcut methods useful of competitive exams. But my emphasis is always on concept based method. Just learning the shortcut without understanding concept, is meaningless.Till now I have uploaded 42 videos and I am going to upload many more gradually. Just click below and start watching anytime.Maths In Minutes with Priya best wishes for exam.
Math Word Problem Help! function?
Till 19 hours left for answering no one has calculated the relation between volume and thickness to be coated: *****In fact, I was busy calculating the x for your another cubic equation (0.1=8x^3.....) but that actually was an offshoot of this question you wanted to solve exactly. Friend that equation is wrong (you gave there +28 x^2 term but it actually should have been - 28 x^2 ) Formula: Let us sit at the 3-D center of the room with 3x2 (x,y) area and 2' height ractangular geometry. From that centre, as origin, its dimensions to pair of opposit planes would be (1', 1.5' and 1' respectively). Therefore its volume (V)room without coating = 2(1)* 2(1.5)* 2(1) = 12 ft^3 if x is the thickness of coating then the left over volume of room after coating would be: (V)room with coating = 2[1-x] 2[1.5-x] 2[1-x] Therefore (v)coating = Vc = 12 - 8(1-x^2)(1.5-x) ---(1) this is the sought relationship now given 0.1 = 12 - 8(1-x^2)(1.5-x) simplifying 0.1 = 12 - 4 [(1+x^2-2x) (3 - 2x)] 0.1 = 12 - 4 [3+3x^2 - 6x - 2x - 2x^3 + 4x^2] 0.1 = 12 - 4 [3+7x^2 - 8x - 2x^3] 0.1 = 12 - [12+28x^2 - 32x - 8x^3] 8x^3 -28x^2 + 32x =0.1 ----- (2) This (2) is a very difficult one to get direct exact solution and I could approximate its solution to x = 0.0031331991 (with remainder - 0.00022157) you wanted upto 4-decimal places. Above (2) 80x^3 -280 x^2 + 320x -1=0 80x^3 - 40[7 x^2 - 8x] -1=0 [80x^3 -80] - 40 [7 x^2 - 8x+ 1] -1 +120 =0 add & subtract 120 [80x^3 -80] - 40 [(x-1)(7 x-1)] +119 =0 80 [x^3 -1] - 40 [(x-1)(7 x-1)] +119 =0 80 [(x -1)(x^2+x+1)] - 40 [(x-1)(7 x-1)] +119 =0 40 (x-1) [2x^2+2x+2 - 7x+1] +119=0 40 (x-1) [2x^2 - 5x+3] +119=0 40 (x-1) [2x^2 - 2x-3x+3] +119=0 40 (x-1) [(2x-3)(x-1)] +119=0 40 (x-1)^2 (2x-3) +119=0 ** Pls note that feet (FPS system has spoiled the beauty of exact solution) had it been in MKS system x=1mm = 0.001 would been much easier for students. It is deceptive and suits contractors so that they can easily befool owners by conversion of units into odd one's. Good to have tried - cat in a box type solution.
Math word problem help (ratio 8th grade)?
I'm thinking it is 0.896 in each bag. Because if you take 0.672kg and divide is by 3 (for the 3 parts), you get 0.224 (which is one part). Then you take that one part and multiple it by 8 (for the 8 parts) and you get 1.792 (total for 8 parts) but you have to divided that by 2 because there were two bags and you get 0.896 kg per bag. I hope this helps.