Which is correct, "Is there anything else that I can help you with today? Or Can I help you with anything else today?"
Both are equally correct. However, the first one is just slightly more clunky than the second.“Is there anything else that I can help you with today” is a bit wordy. The words ‘that’ and ‘today’ are both unnecessary. A simpler form of both sentences that serve both functions is: “Can I help you with anything else?”Or, if you’re going for something more professional: “Do you require any more assistance?”However, if you must choose between the two, I would say that the second sentence is more correct, if only because it flows better than the other one.
Need some pc help plz guys?
1. You can receive e-mail, but you cannot send it. What type of e-mail server may becausing the problem? 2. What is the best method for sending the content of a word processor document toanother person via e-mail? 3. Why would an alarm feature be useful in PIM software? 4. Which choice lists all the protocols necessary to send and receive e-mail? 5. Which method allows you to save your Web-based e-mail messages to your hard drive?
Can someone help me with hybridization?
(a) The rule for hybridization: All sigma bonds (single bonds and only one bond in double or triple bonds) and lone pairs (nonbonding pairs) are found in hybrid orbitals. Since it is impossible to draw a structural formula in the answer part, it will be difficult to explain, but I'll try. Ethyl acetate: CH3 -- C = O .............................. I .............................. O -- CH2 --CH3 I think you understand the structure. First C atom has 4 single (sigma) bonds. therefore its type of hybridization is sp3 (1 s and 3 p = 4) Second C atom has 2 single(sigma) and 1 double bond (one of them is sigma , the other is pi bond). Total sigma bonds : 3. Since only sigma bonds are hybridized, its type of hybridization is sp2 (1 s and 2 p = 4) Third C atom has 4 single (sigma) bonds. (one with oxygen, one with 4th C atom and 2 with H atoms). Total sigma bonds: 4 and therefore the type of hybridization is sp3. Finaly the fourth C atom is like the first one and the type of the hybridization is sp3. (b) Each C atom has 4 valence electrons (Group IV A) 4 C atoms have 16 valence electrons. Each O atom has 6 valence electrons (Group VI A) 2 O atoms have 12 valence electrons. Each H atom has 1 valence electron and total 8 H atoms have 8 valence electrons. Hence, the total number of valence electrons in ethylacetate molecule is 16 + 12 + 8 = 36 (c) All valence electrons of C and H atoms are used to make bonds (16 + 8 = 24). In addition 2 electrons of each O atom are used to make bonds (each O atom has 2 bonds) Valence electrons used by O to make bonds : 4 Total valence electrons used for making bonds are : 28 (d) I think c and d ask the same question. (e) 28 valence electrons are used to make bonds out of 36, and 8 valence electrons (4 of each O atom) remain in nonbonding pair. Note: in the molecule there are 14 bonding pair and 4 nonbonding pair (lone pair).
Please Help with Satistics !!! For each of the following, assume you are working with a standard deck of 52 cards. There are 13 cards...?
For each of the following, assume you are working with a standard deck of 52 cards. There are 13 cards (2, 3, 4, 5, 6, 7, 8, 9, 10, Jack, Queen, King, and Ace) in each of four suits (Clubs, Diamonds, Hearts, and Spades). a) What is the P(Club) when drawing one card? b) What is the P(Jack) when drawing one card? c) What is the P(Jack ∩Club) when drawing one card? d) What is the P(Jack∪Club) when drawing one card? e) What is the P(Jack|Face Card) when drawing one card? This roughly translates to what is the probability of getting a Jack if you know the card is a face card. f) What is the P(Red|Heart) when drawing one card?
Calculus word problem help?
Let p be the price of an item and q be the number of items sold at that price, where q=f(p). What do the following quantities mean in terms of prices and quantities sold? 1. is the f (35) A. average price of the first 35 items sold. B. revenue generated by the sale of 35 items. C. rate at which items are sold when the price is 35. D. median number of items sold if the price is no more than 35. E. number of items sold when the price is 35. F. rate at which the price is changing when 35 items are sold. G. price for which 35 items are sold 2. is the f ^ -1 (45) A. price at which 45 items will be sold. B. revenue generated by the sale of 45 items. C. number of the first 45 items that are returned for refund. D. rate at which items are sold when the price is 45. E. rate at which the price is changing when 45 items are sold. F. average price of the first 45 items sold. G. number of items sold when the price is 45.
Acids and Bases and pH Chemistry...can someone please help me?!?
"A. What are the equilibrium concentrations of C9H7O4- and H3O+? For this I calculated both their concentrations to be 0.0017 M by using the Ka and plugging in the other values I already know." You can check your work by calculating Ka from your concentrations: Ka = [H3O^+][C9H7O4^-]/[HC9H7O4] = (0.0017)*(0.0017)/(0.100 - 0.0017) = 2.940 x 10^-5 That's close, so I think the difference is due to rounding up to two sig figs. You just need to express your answer, 0.0017, to three sig figs instead of 2 sig figs. I got 0.00164 (to 3 sig figs), and that works out. "B. What is the equilibrium concentration of OH- and the pH of the solution at 25C? I answered this by using the concentration I found for H+ and plugging it into the pH equation and got 2.8 as the answer. Then I used [OH-][H+] = 1E-14 to find that 5.88E-12 M." Again, use the concentration expressed to three sig figs. Using 0.00164, I get pH = 2.785 (four sig figs, rounds to 2.79), That makes pOH = 11.21 and [OH^-] = 6.10E-12 M. "C. What is the Kb for the reaction? C9H7O4- +H2O <-->HC9H7O4 + OH- For this I used Kb=Kw/Ka and I got 3.64E-10" That is correct. Here's (D): "D. To 200.0 mL of the original solution, 3.03 g of sodium acetylsalicylate, NaC9H7O4 (MM = 202.142 g/mol), is added. The salt dissolves completely and the volume of the solution remains unchanged. Calculate the pH of the resulting solution at 25C. I converted the 3.03 g of NaC9H7O4 to moles and got 0.015 moles of NaC9H7O4 that were added but I'm very unsure about what to do from there....please help!" For that, we need to recognize that we now have a solution of a weak acid and its salt. Such problems are solved using the Henderson-Hasselbalch equation: http://en.wikipedia.org/wiki/Henderson%E... pH = pKa + log([A^-]/[HA]) We use the "raw" concentrations for this calculation. [A^-] = ((3.03 g NaC9H7O4)/(202.142 g/mol))/0.2000 L) = (0.01499 moles)/(0.2000 L) = 0.0749 M [HA] = 0.100 M pKa = -log(Ka) = -log(2.75E-5) = 4.561 Now plug in the values pH = pKa + log([A^-]/[HA]) pH = 4.561 + log((0.0749 M)/(0.100 M)) = 4.561 - (-0,125) = 4.686 = 4.69 to three sig figs
Punnett Square Genetics Problem! 10 points!!!! Help please!?
Say B = barking, b = silent, E = erect e = droopy The heterozygous dog is BbEe The droopy silent dog is bbee so the hetero dog can produce: BE Be bE be the homozygous dog can only produce be combining these two shows that the two dogs together can produce: BE + be = BbEe which is barking and erect Be + be = Bbee which is barking and droopy bE + be = bbEe which is silent and erect be + be = bbee which is silent and droopy The probability of each of these is equaly likely, so the probability of getting a barking dog with droopy ears is 1 in 4 or 25%
Could someone please help with this physics question?
A proton traveling with speed 2e5 m/s in the -z direction passes through a region in which there is a uniform magnetic field of magnitude 0.8 T in the -x direction. You want to keep the proton traveling in a straight line at constant speed. To do this, you can turn on an apparatus that can create a uniform electric field throughout the region. What electric field should you apply? In what direction?