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Physics homework help!?

Certain insects can achieve seemingly impossible accelerations while jumping. The click beetle accelerates at an astonishing 400g over a distance of 0.52 cm as it rapidly bends its thorax, making the "click" that gives it its name.

Q) ignoring air resistance, how high would it go?

Physics homework help....?

Here you need to use the gravitational force :

the gravitational force will be equal to the centripetal force of the meteor, because, we can take the neutron star as an sphere, and you know by circular motion and dynamics, that the centripetal force takes to the center of the circle.

G*M*m / r^2 = m*v^2 / r

r = radius

G = constant

M = mass of the star

m = mass of the meteor

G = 6.67*10^-11 (N*m^2 / kg^2)

then :

6.67*10^-11*2.5*10^29*m / (10*1000)^2 = m*v^2 / 10*1000

16.7*10^18 / 10000 = v^2

v = 4.08*10^7 m/s

This is a lot of speed, but hope that's the answer.

Check it step by step.

Physics homework help?

Three blocks are connected on the table as shown in Figure P5.44. The table is rough and has a coefficient of kinetic friction of 0.440. The objects have masses of 4.00 kg, 1.00 kg and 2.00 kg, as shown, and the pulleys are frictionless.


Figure P5.44
- http://www.webassign.net/pse/p5-50.gif

(a) Draw free-body diagrams of each of the objects. (Do this on paper. Your instructor may ask you to turn in this work.)

(b) Determine the acceleration of each object and their directions.
with a 4 kg mass
(c) Determine the tensions in the two cords.
please find the N (left cord)
and the N (right cord)

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Assuming this isn't your homework, here is the solution. If it is then shame on you.

The collision is inelastic so we can assume that for a non-relativistic collision the two bodies will coalesce and release energy. In all collisions momentum is conserved; whether they are relativistic or not. Thus

Equation (1): m.v1 - m.v2 = 2m.V

Solving this we get

Equation (2): V= 1 m/s (this moves in the +ve x-direction)


Energy is not conserved. Thus

KE(initial) - KE(final) = KE(change)


Therefore

KE1 + KE2 = KE(change)


(.5m.v1^2 + .5m.v2^2) - .5(2m)V = KE(change)

Substituting and solving gives

KE(change) = 25m J


David

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