If three coins are tossed simultaneously, what is the probability of getting at least two heads?
First, consider all the ways that the three coins could land:For each coin, there are two possibilities, heads or tails, so for the three coins, the number of possibilities is:2 x 2 x 2 = 8 possibilitiesi.e. HHH / HHT / HTH / THH / TTT / TTH / THT / HTTOut of these total possibilities, there are four ways to get two heads:HHT / HTH / THH / HHHSo, the chances of getting at least two heads when tossing three coins at the same time is 4/8 or 50 percent.
Math homework help? probability.?
Katrina-Ballerina Sorry to hear that no one in your class understands it ... it is really quite simple ... Let's say you have a spinner with values 1 through 6. Each value on the spinner has the same probability or 1/6. The expected value is simply the sum of 1 through 6 divided by the number of values or 6. So, in this example: Expected Value = (1+2+3+4+5+6) / 6 = 3.5 points Now, you can "simulate" this same "spinner" problem by rolling a dice. The die has values 1-6, so roll the dice say 25 times and add up the points for each throw. Finally, divide the total points by 25 and that number should be approximately equal to 3.5 Make sense? Now, your problem isn't much different. First note that the probability of 0 points is 100% - 60% - 5% = 35% Expected value = [(35 x 0) + (60 x 1) + (5 x 3)] / 100 = 0.75 points In order to "simulate" this problem you will need a deck of cards with the numbers 1 - 100. Assign the following values to the card ... 1 - 35 = 0 points 36 - 95 = 1 point 96 - 100 = 3 points Now, pick say 100 cards "replacing" the card back into the deck and shuffle each time. Record the number of points for each of the 100 draws. Add up all the points for the 100 cards, then divide by 100. The result should be very close to 0.75 points. Hope that helped