TI 84 ***How can I find the x value from a given y value on a graph?
Hello! Im using a blue ti 84 calc. So imagine that I have a graph, and I want to know what the x value is when y = 16.73 , is there a way of doing this. I can use the CALC and 1:VALUE on the calculator to find the y value of a given x value but now i want to do the reverse. I've been trying to do TRACE and TABLE functions but the values i get are very rough and i cant get it to exactly 16.73. THANKYOU !!!!!
Does it matter which value you pick for x when you graph a line by plotting points. Explain your reasoning?
No, it doesn't matter. The shape of the curve is determined by the equation. If its linear (of degree 1) then it will be purely a straight line, either sloping or down. If its of a higher degree like a quadratic or cubic equation, it will be concave in its appearance as you probably already know. If no domain is precisely specified, you can use any value of x. It would be best to start at zero, and say go up to ten. You plot your two axes, insert the various values of x from 0 through 10, and plot the corresponding points. An example, take a really, really, really easy function like y = 2x. You are choosing values of x to be 1, 2, 3,...,10. So get to work and see what this looks like. You know already it'll be linear, and positive. Or, you could plot just two points, substitute x = 2, and x = 10, plot the points and connect them with a single straight line. You could also start with x = 14 and compute through x = 30 and the line will still be the same, because for every value of x, no matter what it is, y will be just two times the value of x.
Use the graph below to find the integer value(s) of x where the limit does not equal a finite value as x approaches those integer value(s).?
Let's consider them one by one. At x = -2, there isn't a specific y value because there is an open circle. But the limit (as long as you approach from the right) would be -4. So that's not one to add to your list. At x = -1, when you come from the left or the right, you approach the value of -1. Interestingly, the function at that point is actually -2, but the limit would be what the neighboring values are approaching which is actually -1. Again, this is not one to add to your list. Yes, the function has a discontinuity at this point (known as a removable discontinuity), but a finite limit still exists. At x = 1, we have a discontinuity where we get two different values if we come from the left vs. the right. Coming from the left, we are approaching -1, but from the right we hit 2. This would be one to add to the list since there isn't a single limit. At x = 3, we have the value getting really small (approaching negative infinity). That's not a finite value, so x = 3 should be added to your list. At x = 5, we are again at an endpoint. The limit approaching from the left would be the actual value of the function being 0. Answer: x = 1 and x = 3
Determine graphically the x value when y 3 in the given equation -x+3y=12?
I was confused by the y 3 thing so I am assuming you want this simplified so you can graph it To graph -x+3y=12 you have to get y by itself. So here we go: -x + 3y = 12 First add x to both sides 3y = 12 + x Divide by 3 to both sides y = (12 + x) / 3 Simplify the fraction y = 4 + X/3 Boom! y = X/3 + 4 This is the same thing as the previous thing. Type that on a graphing calculator and you should get your answer. Or know that it starts at 4 when X equals 0 and moves up 1 every 3 it moves across. In other words it is a line.
How do I find the corresponding value for a given data and graph in Excel?
What you are really asking for is not to read data from the chart, but to interpolate values from the data you originally put into it. In the data you provided there simply is no data pair (x,50), so your chart will never be able to return x without doing some kind of interpolation between the two surrounding points (2.5,55) and (5,32).Of course Excel shows lines between the points in your chart, and that suggest that there is data, but there really isn't. The lines are simply a linear or some kind of polynomal interpolation between the surrounding points.So the only right way to do this is by adding a trend line.Select your data points and choose insert trend line. It is up to you to decide whether it will be a linear trend line, a logarithmic or a 3rd order polynomal. Make sure you check the "show equation" box. Then Excel will add a trendline and show its equation. Using that equation you can simply calculate X from any given Y. As far as I know the only way to do this is type the equation manually in your workbook. Keep in mind however that any trend line is always an approximation, and that you better not use it to extrapolate.Below two screenshots (in Dutch).
What value is placed on the x-axis in a graph?
In a two-dimensional graph, (with two axes), generally the independent variable is plotted on the x-axis and the dependent variable is plotted on the y-axis. In layman’s terms, you can say that the y-axis contains “what you are measuring” and the x-axis contains “what you are measuring at / against / with respect to”.For example, say you are plotting distance traveled in a car against time. Clearly the flow of time is independent of the travelling of distance by the car. If even there was no car, you would still have time flowing.Thus you would place time on the x-axis and distance on the y-axis.
How do I use a given graph of the function to find the x-values for which f is discontinuous?
An easy way to think about discontinuity is that a discontinuity exists whenever you cannot draw that part of the graph without lifting up your pencil. Using this definition, this function is discontinuous when [math]x=-2, 2, 4[/math].
How to determine the function value using a graph?
Hi, Your problem seems to be function notation, like f(2) or f(-2). f(x) in an equation is really the same as y, so f(x) = x + 2 is really the linear equation y = x + 2. Hopefully that equation in slope-intercept form is easy for you. For f(x) = x + 2, to find f(2), simply plug in 2 for x and solve for its y or f(2) value. f(x) = x + 2 f(2) = 2 + 2 f(2) = 4 This means that (2,4) is a point on the graph of f(x) = x + 2. To find f(2) by looking at a graph, go on the x axis to where x = 2. Then go either up or down to the point on your function, and determine that point's y value. That point's y value is f(2). Likewise, to find f(-2) by looking at a graph, go on the x axis to where x = -2. Then go either up or down to the point on your function, and determine that point's y value. That point's y value is f(-2). I hope that helps!! :-)
Is there any app which plots graphs if I put x and y values?
Try GeoGebra . It’s free and opensource.It has an Android Version, a web app ( You also have some cloud storage)It also has native Windows, Mac, Linux Applications.I have used it for 3 years, found it really useful when my brothers asks me about how “this” graph looks etc.All the Best !