How many grams of Helium would it take to fill a blimp that has a volume pf 2.00 x 10^6L?
Use PV = nRT (assuming standard temperature/pressure) (1.00 atm) (2.00x 10^6L) = n (.0821 "*atm/mol*K) (273.15 K) n = 89184 mols (you can also use the shortcut of 22.4L per mol of ideal gas at STP instead) Atomic mass of He is 4.002 g/mol (4.002 g/mol) (89184 mols) = 356913 -> sig figs -> 357000 grams of He
A2A.Yes, it will be able to move. If you fill your car tyres with helium gas your car would move as good as filling it with regular compressed air or nitrogen[1]. As long as you fill your car tyres with any non-reactive (non-corrosive to metal and tube material) gas, you're good to go. The amount(volume) of helium in your tyres would not be able to lift it due to low area.It's just that helium gas is not abundant in the atmosphere and is costly to use it for any purpose where its properties are not employed[2](like buoyancy for weather balloons and inert nature for welding[3], etc).Also due to the light weight of the gas, lighter than air, helium gas is escaping out into space and the earth does not have it in abundance. With the rate at which we are exhausting our resources of helium and losses into the outer space, the earth is soon going to lose all its helium.Moreover, helium is a costly gas due to its inert nature. It costs around 700₹ per litre. So it is neither profitable nor advisable to use it for purposes like filling tyres.Footnotes[1] Is Nitrogen Better than Air in Car Tires?[2] Helium - Wikipedia[3] Gas tungsten arc welding - Wikipedia
A2A.Yes, it will be able to move. If you fill your car tyres with helium gas your car would move as good as filling it with regular compressed air or nitrogen[1]. As long as you fill your car tyres with any non-reactive (non-corrosive to metal and tube material) gas, you're good to go. The amount(volume) of helium in your tyres would not be able to lift it due to low area.It's just that helium gas is not abundant in the atmosphere and is costly to use it for any purpose where its properties are not employed[2](like buoyancy for weather balloons and inert nature for welding[3], etc).Also due to the light weight of the gas, lighter than air, helium gas is escaping out into space and the earth does not have it in abundance. With the rate at which we are exhausting our resources of helium and losses into the outer space, the earth is soon going to lose all its helium.Moreover, helium is a costly gas due to its inert nature. It costs around 700₹ per litre. So it is neither profitable nor advisable to use it for purposes like filling tyres.Footnotes[1] Is Nitrogen Better than Air in Car Tires?[2] Helium - Wikipedia[3] Gas tungsten arc welding - Wikipedia
How many grams of Helium would it take to fill a blimp that has a volume pf 2.00 x 10^6L?
Use PV = nRT (assuming standard temperature/pressure) (1.00 atm) (2.00x 10^6L) = n (.0821 "*atm/mol*K) (273.15 K) n = 89184 mols (you can also use the shortcut of 22.4L per mol of ideal gas at STP instead) Atomic mass of He is 4.002 g/mol (4.002 g/mol) (89184 mols) = 356913 -> sig figs -> 357000 grams of He
Chemistry calculations using formulas and STP to find values? Need help bc I don't understand the formulas.?
1. Determine the volume of a container that holds 2.4 mol of gas as STP. 2. What size container do you need to hold 0.0459 mol N2 gas at STP? 3. What volume will 1.02 mol of carbon monoxide gas occupy at STP? 4. If the pressure exerted by a gas at 25 degrees celsius in a volume of 0.044 L is 3.81 atm, how many moles of gas are present? 5. Dtermine the celsius temperature of 2.49 moles of gas contained in a 1.00-L vessel at a pressure of 143 kPa. 6. Calculate the volume that a 0.323-mol sample of a gas will occupy at 265 K and a pressure of 0.900 atm. 7. What is the pressure in atmospheres of a 0.108-mol sample of helium gas at a temperature of 20.0 degrees celsius if its volume is 0.505 L? 8. Determine the kelvin temperature required for 0.0470 mol of gas to fill a balloon to 1.20 L under 0.988 atm pressure. 9. Propane, C3H8, is a gas commonly used as a home fuel for cooking and heating. a. calculate the volume that 0.540 mol of propane occupies at STP. b. think about the size of this volume compared to the amount of propane that it contains. why do you think propane is usually liquified before it is transported? 10. Hydrogen gas at a temperature of 22.0 degrees celsius that is confined in a 5.00-L cylinder exerts a pressure of 4.20 atm. If the gas is released into a 10.0-L reaction vessel at a temperature of 33.6 degrees celsius, what will be the pressure inside the reaction vessel? 11. A sample of neon gas at a pressure of 1.08 atm fills a flask with a volume of 250 mL at a temperature of 24.0 degress celsius. If the gas is transferred to another flask at 37.2 degrees celsius at a pressure of 2.25 atm, what is the volume of the new flask? 12. What volume of beaker contains exactly 2.23x10 exponet -2 mol of nitrogen gas at STP?
The cat…After enforced metrication, a [math]9[/math] pound moggy is about [math]4.08233 \text{ kg}[/math]At Standard Temperature & Pressure…The density of air at is about [math]1.2754 \text{ kgm}^{-3}[/math]The density of helium is about [math]0.176 \text{ kgm}^{-3}[/math]The density of hydrogen is about is [math]0.089 \text{ kgm}^{-3}[/math]So in terms of lift…Helium generates about [math]1.099[/math] grams of lift per litreHydrogen generates about [math]1.186[/math] grams of lift per litreAir generates absolutely bugger-all lift in a balloon. (You’ll have to build a little airplane and teach the cat to fly!)An [math]11[/math] inch balloon has a volume of approximately…[math]\dfrac{4}{3} \pi \left(\dfrac{11 \times 2.54}{2}\right)^3=11.4203083 \text{ litres}[/math]So you’ll need…[math]\dfrac{4082.33}{1.099}=3714.586 \text{ litres of Helium}[/math]or[math]\dfrac{4082.33}{1.186} =3442.099 \text{ litres of Hydrogen}[/math]So that’s about [math]326[/math] balloons full of Helium or [math]302[/math] balloons of Hydrogen.If we assume that an 11 inch balloon itself weighs a couple of grams (???) - then the net lift capability is reduced and the number of balloons has to be scaled up and probably ends up around [math]400[/math] to [math]450[/math] balloons.(Of course that doesn't include the weight of any strings, or a support-harness for the cat, or indeed a tiny straitjacket for the legitimately worried cat)[Addendum: According to the Balloon industry - an [math]11[/math] inch balloon has a net lift capacity of [math]0.35[/math] ounces. So neutral buoyancy for the cat happens about [math]411[/math] to [math]412[/math] balloons)