What is the relationship between pressure and mass flow rate? Does the mass flow rate increase if there's a pressure increase, and does the mass flow rate decrease if there's a pressure decrease?
There is no relationship between pressure and mass flow when we talk about flows in pipes. For any flow to happen, there is a requirement of pressure gradient and not the pressure. Higher the pressure gradient, keeping all other things (fluid, pipe diameter, length) constant, higher is the mass flow rate. But higher pressure does not reveal anything about the flow. You can have a stagnant fluid with 20 bar pressure in a pipe (consider its valves closed) and you also can have a significant flow in a pipe having pressure gradient of 0.2 bar/m of pipe length.Mass flow is the effect and pressure gradient is the cause of it.
The temperature of a 35.2 g sample of iron increases from 23.7 °C to 29.5 °C. If the specific heat of iron...?
The temperature of a 35.2 g sample of iron increases from 23.7 °C to 29.5 °C. If the specific heat of iron is 0.450 J/g-K, how many joules of heat are absorbed? The temperature of a 35.2 g sample of iron increases from 23.7 °C to 29.5 °C. If the specific heat of iron is 0.450 J/g-K, how many joules of heat are absorbed? a 1.1 x 103 b 4.3 c 1100 d 92 e 0.450
Why is my body temperature always higher than other people's?
Hi Shaylnn Smith,Thank you for your question,How are you gauging this perception of having a higher body temperature than other people, perhaps other people have the same body temperature, and you happen to display symptoms such as warm skin, being flushed, sweating etc. I’m assuming it is your external temperature that is warm, if it is an internal rise in temperature then we have bigger problems such as parasites, infections or virus’.How much water are you drinking?I invite you to try drinking 0.033 x (your body weight in kg) and see if your temperature decreases, and you possibly may feel a lot better flushing out toxins from your body.Are you stressed?If your body is stressed you will release the hormone cortisol, depressing the immune system, leaving you susceptible to colds and virus which would cause an internal rise in temperature, leaving you feeling warm and groggy. Furthermore stress inhibits you from breathing deeply, try some deep breathing techniques, a lack of breathing upsets the acid/base balance which again would upset your thermoregulation i.e raise your temperature.Diet?Say this over and over, are you eating right for your metabolic type? How do you feel after eating breakfast or a meal? Do you have energy or do you feel tired and lethargic, but you can’t be because you have things to do and now your so behind and now you are stressed…see the vicious cycle. Take a look here: http://www.thewonderofcancerblog...There could be a number of other reasons, however if you try sorting them 3 areas out first your problem may be solved. If not send me a private email rstuarthlc@gmail.comSomeone will be able to help you,Hope that helps,Speak soon,R
The molar heat capacity of silver is 25.35 J/mol C. How much energy needed to raise temp of 10.5g Ag by 14.7C?
Use Q = m*c*delta T (where m is mass in grams or moles, c is the specific heat, and delta T is the temperature change in degrees Celsius). Since your specific heat was given in J/mol C, you should convert your given mass of silver to moles of silver: 10.5 g Ag(1 mol Ag/107.87 g Ag) = .097 mol Ag Now, just substitute all quantities to find Q: Q = (.097)(25.35)(14.7) = 36.3 J
Do I bathe with warm or cold water during fever?
Bathing decrease s blood circulation.The purpose of fever is to increase blood circulation
Calculate the amount of heat needed to melt 110 g of solid benzene and bring it to a temperature of...?
Since no initial temperature is given, supposing the problem to begin at 5.49°C: melting the solid: (110 g C6H6) / (78.11236 g C6H6/mol) x (9.87 kJ/mol) = 13.899 kJ heating the liquid: (1.63 J/gK) x (110 g) x (33.2°C - 5.49°C) = 4968 J = 4.968 kJ total: 13.899 kJ + 4.968 kJ = 18.9 kJ
The specific heat of a certain type of metal is 0.128 J/ (g·°C). What is the final temperature if 305 J of heat is added to 78.5 g of this metal initially at 20.0 °C?
Energy, E is the product of mass, m, heat capacity, Cp, and temperature change ΔT,So, E = m•Cp•(T2 – T1)In this case,305 = 78.5 x 0.128 x (T2 – 20)305 + 200.96 = 78.5 x 0.128 x T2Or T2 = 505.96/10.048 = 50.35C