>> my_string = "This is line one">>> my_string = my_string + "\nandthis is line two"print my_stringThis is line oneand this is line twoYou can also use multiline syntax using the treble quote>>> my_stri" /> How To Add Strings To This Code

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How To Add Strings To This Code

How do I add a new line in a string in python?

Code examples in Python2 - Python3 is the same (just needs brackets on the print).a new line in a string is denoted by `\n` .. :>>> print "This is line one\nand this is line two"
This is line one
and this is line two
to add a line to an existing string :>>> my_string = "This is line one"
>>> my_string = my_string + "\nandthis is line two"
print my_string
This is line one
and this is line two
You can also use multiline syntax using the treble quote>>> my_string = """This is line one
... and this is line two"""
>>> print my_string

This is line one
and this is line two
when you use the treble quote sytntax you don’t need to include the ‘\n’ and you can easily include indents etc and the string uses every single character within the string :>>> my_string = """This is line one
... and this is line two"""
>>> print my_string

This is line one
and this is line two

How can I write HTML code as a JavaScript string?

Hiii friends,If you need to use html as a javascript string . I am providing you with a very easytechnique . There are a lot of techniques ,so we are going to see a few of them .by putting html tags with in inverted commas(“”)var a = “

hello user

”;—— so this line will create a variable a which will store your html in itdocument.write(a);———and this above line will print the value of a variable2 . Use the concatenation operator (+)
Thanks .

How to add loop on this code?

#include
#include
using namespace std;

int main() {
string name;
cout <<"Enter your name: " << endl;
getline(cin, name);
double gross;
cout<<"Enter gross amout: " << endl;
cin>>gross;
cout< cout< cout< double federal = gross*0.15;
cout<<"Federal Tax: "< double state = gross*0.035;
cout<<"State Tax: "< double social = gross*0.0575;
cout<<"Social Security: "< double medical = gross*0.0275;
cout<<"Medicare/Medicaid Tax: "< double pension = gross*0.05;
cout<<"Pension Plan: "< double health = 75;
cout<<"Health Insurance: "< double net = gross-(federal+state+social+medical+pens...
cout<<"Net Pay: "< return 0;
}

How do I take two strings and add them to each other based off of their integer value equivalent?

It will only let me enter 1000 chars so ill post a few tiny pieces of it.
Heres my constructor:

public LetterInventory(String data)
{
String lowerCase = data.toLowerCase();
this.data = "";
for (int i = 0; i < lowerCase.length(); i++)
{
char j = lowerCase.charAt(i);
if (Character.isLetter(j))
{
size++;
int k = j - 'a';
countLetters[k]++;
data += j;
}

}
}

My add method.

/* Constructs and returns a new LetterInventory object that represents the sum of this letter
* inventory and the other given LetterInventory. The counts for each letter should be added
* together. The two LetterInventory objects being added together (this and other) should not
* be changed by this method
*/
public LetterInventory add(LetterInventory other)
{
LetterInventory addLetters = new LetterInventory(this.data + other);
return addLetters;
}

How to concatenate a string and an int in C++?

I am trying to concatenate a string and an integer (portnumber) in a C++ program, but I am confused about how to do this.

Here is my code

#include
#include
#include
#include

using namespace std;

int main()
{
char option;

cout << "Network Security Commands" << endl;
cout << "=========================" << endl;


cout << "1. Display Current firewall Configuration" << endl;
cout << "2. Block All Outgoing traffic by protocol port Number" << endl;

cout << "Enter an option" << endl;
cin >> option;

switch (option)
{
case '1':
system("iptables -L");
break;
case '2':
int portnumber;
cout << "Enter the Protocol Port Number" << endl;
cin >> portnumber;
string command;
command = "iptables -A OUTPUT -p tcp --dport " + portnumber + " -j DROP";
system (command.c_str());
break;
}


return 0;
}


I know I have to so something with portnumber, but I am stuck.

Help me solve my code grinder question?

Description
In this exercise your function receives a list containing two strings and returns a new string that displays these two strings as a sentence. Remember to include a space.

Function Name
concat

Parameters
words : a list containing two string values
Return Value
a string that is the two strings of the list combined with a space between them.

How do I add two strings in Java using the "+" operator for runtime input?

Firstly, there's a slight difference in semantics. If a is null, then a.concat(b) throws a NullPointerException but a+=b will treat the original value of a as if it were null. Furthermore, the concat() method only accepts String values while the + operator will silently convert the argument to a String (using the toString() method for objects). So the concat() method is more strict in what it accepts.To look under the hood, write a simple class with a += b;public class Concat {
String cat(String a, String b) {
a += b;
return a;
}
}
Now disassemble with javap -c (included in the Sun JDK). You should see a listing including:java.lang.String cat(java.lang.String, java.lang.String);
Code:
0: new #2; //class java/lang/StringBuilder
3: dup
4: invokespecial #3; //Method java/lang/StringBuilder."":()V
7: aload_1
8: invokevirtual #4; //Method java/lang/StringBuilder.append:(Ljava/lang/String;)Ljava/lang/StringBuilder;
11: aload_2
12: invokevirtual #4; //Method java/lang/StringBuilder.append:(Ljava/lang/String;)Ljava/lang/StringBuilder;
15: invokevirtual #5; //Method java/lang/StringBuilder.toString:()Ljava/lang/ String;
18: astore_1
19: aload_1
20: areturn
So, a += b is the equivalent ofa = new StringBuilder()
.append(a)
.append(b)
.toString();
The concat method should be faster. However, with more strings the StringBuilder method wins, at least in terms of performance.The source code of String and StringBuilder (and its package-private base class) is available in src.zip of the Sun JDK. You can see that you are building up a char array (resizing as necessary) and then throwing it away when you create the final String. In practice memory allocation is surprisingly fast.

With JavaScript, how do you add new words to a string?

I'm always trying to abstract the code I write, in order write less code in the future...Take a look at the following code, it uses the String.prototype.replace() method coupled with a new RegExp() to create an expression out of a variable. All of this is wrapped in a function that can be integrated into any project's code modules.
function interpose( str, pattern, replace ) {
return ( str || "" ).replace( new RegExp(pattern, "g"), replace );
}

console.log(

// Your text
[ "Welcome to our town", interpose( "Welcome to our town", "our", "our small" ) ]

);

console.log(

// With a Regular Expression
[ "Welcome to our town", interpose( "Welcome to our town", "(our)", "$1 small" ) ]

);


console.log(

// With a Regular Expression
[ "Welcome to our town", interpose( "Welcome to our town", "^", "You're NOT " ) ]

);


console.log(

// An integrity test
[ "", interpose( "", "", "the omega" ) ]

);
Running the code above will output the following:
["Welcome to our town", "Welcome to our small town"]

["Welcome to our town", "Welcome to our small town"]

["Welcome to our town", "You're NOT Welcome to our town"]

["", "the omega"]
The only downside to this is that I've harcoded the global flag - which can easily be removed or even made to be part of the argument list.

Java: When we concatenate two strings using the "+" operator, will the resulting string be stored in the string literal pool or not?

In Short answer is "test" will be stored in String Pool.Why? check detail explanation below. There are two ways to construct a string: implicit construction by assigning a string literal 1.String strLiteral = "Java";If you create object using String literal syntax e.g. "Java", it may return an existing object from String pool (a cache of String object)if it's already exists. Otherwise it will create and put in string pool for future re-use.or explicitly creating a String object via the new operator and constructor. 2.String strObject = new String("Java");When you create String object using new() operator, it always create a new object in heap memory.It also will be added to the String constants pool. when you use + it will create new String Literal and concatenate those two string in newly created String Literal (because String are Immutable in JAVA)In your case.String te = "te";(added in String constants pool )
String st = new String("st");(crate new object in heap Plus added in String constants pool ))

String test = te + st;(it will add another string "test" in String constants pool because String are Immutable in JAVA)

Write a code using C++ fragment that will use the “+” operator to append the string username to the string message and store it into?

the string message_buffer where the username is first bracketed by the strings “{[” and “]}”. The strings are defined as follows:
string username = “Paul”;
string message = “Please join our message group!”;
string message_buffer;
After executing your code fragment, message_buffer must contain the following string:
{[Paul]}Please join our message group!


Also:

Write the code fragment that will use the above code to allow the program to prepend more user name and message into message buffer created in.
string username2 = “Martha”;
string message2 = “Wazzup!”;
After executing the code fragment, message_buffer should contain the following
string:
{[Martha]}Wazzup!{[Paul]}Please join our message group!

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