Is My Answer Correct For This Algebraic Problem

Is my answer to this algebra question correct?

Yeah this is correct.I'll do a more simpler example to reassure you, that you are correct.If i start off with £2 and you double your money every year, how much money will you have at the end of 3 years.So at the end of the first year it will double so:£2 x 2 = £4 (Year 1)At the end of the second year you will have:£4 x 2 = 8 (Year 2)Another way of writing this is to say you will have:£2 x (2 x 2) = £8At the end of the third year you will have £16.Another way to write this is £2 x (2 x 2 x 2) = £2 x [math]2^3[/math]The general formula will therefore be:The orginial amount multiplied by the amount you are compounding by (doubling, tripling) to the power of how many times it compounds. So if you are doubling for 5 years with £3.It would be £3 x [math]2^5[/math]Now onto your answer. The thing you did right was finding out how many times it really compounds, which is calculated by, first changing 24 hours into minutes:24 hours = 1440 minutes However, since it does not multiply every minute you divided it by 20 minutes.[math] 1440/20 = 72 [/math]so it starts off with one bacteria then doubles 72 times.So 1 x [math]2^72[/math]Which should give the answer you got.I took the liberty of writing out how to exactly, get the answer because you wrote  [math]2 x 2^71[/math]Which is the same thing, but i don't know how you arrived at that answer. A simple yes would leave a lot of uncertainty. I hope i helped you get this topic. Tara!

Are my answers to these algebra questions correct?

#17. Your answer is incorrect, because the middle pipe's time should be 12, not 6. (Its time should be double the largest pipe's time, unless I am misreading the question.) However, if using 12, those 3 times would not lead to filling the pipe in 3 hours.The appropriate setup for this problem would be [math]\frac{1}{x}+\frac{1}{2x}+\frac{1}{3x}=\frac{1}{3}[/math]#18. EDIT: This answer is correct. [math]\frac{1}{3}+\frac{1}{6} = \frac{1}{2}[/math]#19. This answer is correct. It would take Bill 9 hours. Jodie worked for 8 hours at a rate of 1 garden per 12 hours, and Bill worked for 3 hours at a rate of 1 garden per 9 hours.8hours(1 garden/12 hours) + 3 hours(1 garden/9 hours) = 1 garden#20. This answer is correct. 1 garden/21 hours + 1 garden/28 hours = 1 garden/12 hours

What is the correct answer of [6/2(2+1)], 1 or 9?

Let's analyse this problem as it is originally written.[6÷2(2+1)]BODMAS Convention (Mathematical/scientific calculators):Solve Brackets (box)6÷2(2+1)Solve Brackets (round)6÷2(3)Divide6÷6Answer1Standard left-to-right reads (computing devices)3(2+1)(3*2)+(3*1)(6)+(3)9Having said that, it is important to note the difference between 2(3) and 2*3 (or 2 x 3).2(3) is a single factor since there is no operator separating the two numbers, which binds them more tightly. A hidden operator binds strongly than an expressed operator.2*3 is NOT a single factor, and rather a set of two factors bound by an operator.The BODMAS convention follows the order of operations as follows :Solve Brackets (box, then curly, then round)Solve the orders of operation (roots, powers, etc.)Division (/ or ÷)Multiplication (* or x)AdditionSubtractionDue to absence of correctly used parenthesis, the problem is devised in a, more likely, ambiguous manner. Following can be better notations :(6/2)(1+2)6/[2(1+2)]On a Casio fx-991EX scientific calculator (courtesy and images by @Rashi Chawla), when one enters the problem in its original form :it returns answer as 1, with the change of problem notation, in accordance with BODMAS convention :For a more comprehensive note, you may want to read the following answers too :Peter Vanroose's answer to What is the correct answer of [6/2(2+1)], 1 or 9?Gábor Schermann's answer to What is the correct answer of [6/2(2+1)], 1 or 9?Atul Sinha's answer to What is the correct answer of [6/2(2+1)], 1 or 9?

How do you solve this algebra problem?

The problem is not giving enough information. So far, there are a few good attempts at solving it:In my opinion, Keano Rich  has gotten closest to the correct answer. However, in that answer the assumption is made that everyone drank beer, wine or soft drinks, and no one had, say, a beer followed by a soft drink. Also, no one had more than 1 drink. Not a very exciting party. People must have gotten pretty thirsty.User and User have another attempt, but assume all the people at the party drank wine, beer and soft drinks (hard to imagine, everyone mixing beer and wine, and there being no designated drivers). This might have been the intended solution, but in that case the problem is badly phrased and should specify this.Since we are not told anything specific about whether everyone stuck to 1 drink or whether they mixed different types of drinks, the answer could be anywhere from 2 people (drinking 65 bottles of beer between them) up to any number, where lots of people did not drink anything at all. We need more information.