Monochromatic light passes through a diffraction grating that has 8900 lines/cm...?
Monochromatic light passes through a diffraction grating that has 8900 lines/cm. The second order lines occur at 72.9 degrees. What is the wavelength of the light in nm?
Light from an argon laser strikes a diffraction grating that has 5335 grooves per centimeter. The central and?
the angle of the first maximum with the center is a = tan^-1(0.488/1.77) = 15.41° the grating distance g is 1/5335 cm = 1.8744*10^-6 m and the equation for the wavelength is λ(n) = g*sin(a)/n with n = 1 λ = 1.8744*10^-6*sin(15.41°) λ = 498*10^-9 m <-- ans. OG
As monochromatic light passes through a diffraction grating what is the difference between the path length of?
For a diffraction grating we have d*sin(θ) = m*λ Interference patterns are caused by the path difference between 2 coherent light sources traveling along different paths. When the path difference between the light from adjacent slits is equal to the wavelength, λ, the waves will all be in phase.This occurs at angles θm which satisfy the relationship d sin(θm)/λ = |m| where d is the separation of the slits and m is an integer. Those angles, θm, for which the path difference between the light from adjacent slits is equal to an integral # of the wavelength, λ, and is such that the waves will all be in phase. Thus, the diffracted light will have maxima at angles θm given by d sin (θm) = mλ y(separation between bands) = λ L/d where λ is the wavelength of the light, L is the distance between slits and screen and d is the distance between slits. hope this helps!
What will result if the number of lines in a diffraction grating of a given width is increased?
the interference of the waves don't meet until they are further apart so the spectrum is broader
A diffraction grating has 2500 lines per centimeter. What is the distance between any two consecutive lines?
1 cm = 10mm 10mm / 2500 lines = 0.004mm between lines.
A diffraction grating has 5600 lines/cm. When a beam of monochromatic light goes through it, the second pair o
m lambda = d sin theta lambda = sin theta / (m (1/d)) They give you 1/d and m (2). Theta = arctan (distance along screen / distance to screen) b) Then find theta for the next m (3). theta3 = arcsine (m lambda (1/d)) = arcsine (3/2 sin theta2) And use distance on screen = distance to screen tangent (theta) to get the answer to (b)
A diffraction grating has 4.270 ✕ 103 rulings per centimeter.?
A diffraction grating has 4.270 ✕ 103 rulings per centimeter. The screen is 2.110 m from the grating. In parts (a) through (d), round each result to five significant figures, using the rounded values for subsequent calculations. (a) Compute the value of d, the distance between adjacent rulings. Express the answer in meters. (b) Calculate the angle of the second-order maximum made by the 589.0-nm wavelength of sodium. (c) Find the position of this second-order maximum on the screen. (d) Repeat parts (b) and (c) for the second-order maximum of the 589.6-nm wavelength of sodium, finding the angle and position on the screen. (e) What is the distance between the two second-order maxima on the screen? (f) Now find the distance between the two second-order maxima without rounding, carrying all digits in calculator memory. How many significant digits are in agreement? What can you conclude about rounding and the use of intermediate answers in this case?
Why is mercury light used in a diffraction grating experiment?
reference: http://people.uncw.edu/olszewski...Mercury is a heavy element (Atomic Number = 80) that exists as a liquid at room temperature, and is easily volatilized to a vapor. This makes it an ideal candidate for using in a mercury lamp.Mercury atoms, when excited by electric current, can emit a number of different frequencies (wave lengths) because there are a number of Hg atomic orbitals that are accessible for electronic transitions. The energy that is emitted during de-excitation of electrons from a number of these excited states are in the visible range of the electromagnetic spectrum. These lines can then be used as a source for diffraction grating studies, particularly to study optical interference phenomenon.In contrast, a sodium vapor lamp emits only a single yellow wavelength (D-line) in the visible range of the spectrum. Also, if you used an incandescent lamp, there is a plethora of visible lines that are emitted, which would confound and complicate the diffraction grating experiment.In theory, other elements can also be used in place of mercury, but the easy availability and high volatility of mercury made it a fairly obvious choice to develop a vapor lamp, as a source of visible light of specific frequencies.
What is the function of diffraction grating?
This question has already been addressed here! What is a diffraction grating? But I’ll repost anyways.A diffraction grating acts like a prism to separate light into parts based on wavelength. It has small, usually periodic features that distort the angle of the incident light.The polychromatic (multi wavelength) light source is composed of monochromatic (single wavelength) constituents. Upon interacting with the diffraction grating, light of various wavelengths spread at varying degrees. For more information on the effect of wavelength on diffraction see: How do shorter wavelengths of light provide higher spatial resolution images at smaller scales?Diffraction gratings are used in systems needing high resolution separation of wavelengths. One of the most common uses is in a laser - like the green laser below - in which a monochromatic light source is an important feature to induce lasing.Other common uses include various forms of spectroscopy, which use diffraction gratings to separate an unknown source of radiation into its spectra. An exciting application of spectroscopy is the analysis of gas spectra of cosmological bodies. By breaking up the electromagnetic radiation from distant stars into their spectra, we are able to know more about their chemical composition.Images:Optical Spectrometers, Diffraction grating - Wikipedia