Pressure and Buoyancy?
It is well known that you can trap water in a drinking straw by placing the tip of your finger over the top while the straw is in the water, and then lifting it out. The inner diameter of the straw is 0.5 cm; the height of the trapped water column inside the straw is 5.0 cm. Find the pressure in the air pocket between your finger and the water.
Physics Question,,Help me ,,Buoyancy and pressure?
1) γ = ρ’/ρ = 0.8 = ρ’/1000, => wood density: ρ’ = 800 kg/m³ total mass of buoy + load = 90 kg = mass of displaced h2o V = m/ρ = 90/1000 = 0.09 m³ => volume of displaced h2o = Ax where, immersion depth: x, Volume of material of buoy = m/ρ’ = 80/800 = 0.1 m³ = Ah = A*3 A = 0.1/3 = 0.033 0.09 = Ax, x = 0.09/0.033 = 2.7 m 3 – 2.7 = 0.3 m Or; Specific gravity x height = 0.8 * 3 => 2.4 m of the buoy is submerged. Adding 10 kg of mass will raise the density of the buoy by (90/80)* 0.8 = 0.9 Now 0.9 * 3 = 2.7 m, therefore, 2.7 - 2.4 = 0.3 m of the buoy is displaced by the extra mass Answer is 0.30 m 2) Wmetal = W = γ(ρ_h2o)Vg = 7.8*1000V*9.81, where, specific gravity for nitrobenzene: γ' = 1.2 γ' = W/W – W’ = 1.2 = 7.8*1000V*9.81 / (7.8*1000V*9.81 - 0.429*9.81) 0.2(7.8*1000V*9.81) = 1.2(0.429*9.81) V = 1.2(0.429*9.81)/ 0.2(7.8*1000*9.81) = 5.05 / 1.53x10^4 = 3.3x10^-4 m³
Physics: buoyancy, pressure, volume?
1. This is a table problem. What is the buoyancy of a 25 kg piece of gold in water? (photo) 2. If a second person with 70 kg stands on the platform, how high would they raise the elephant in the previous problem if the density of the fluid was 890 kg/m^3? (photo) 3. How far down will the two students move? (photo) 4. This is a table problem. What is the mass of a 10 cm X 20 cm X 40 cm block of solid lead? a) 904 kg b) 90.4 kg c) 9.04 kg d) .904 kg 5. What additional pressure does a diver feel 25 m below the surface of water? a) 2.42 ATM b) 2.45 ATM c) 242,000 ATM d) 245,000 ATM 6. This is a table problem. What is the buoyancy of a 25 kg piece of gold in water? a) 12.7 N b) 15.9 N c) 38.5 N d) 57.8 N
Is there any relation between total pressure and buoyancy force?
Depends on matter compressibility, a submarine vessel reduces its volume with external pressure (same happens with water but in less degree) then the bouyancy changes and tends to sink unless balast compensation is done.I wondered if the rocket acceleration might be reduced for any living passenger by just inmersing him/her in water (lungs oxigenated water filled as well) and replace the acceleration by pressure effort but then another problem arose, internal organs have different density and bouyant efforts will be magnified by the extra pressure, no good for keeping the life running.
Physics: buoyancy, pressure, volume? (10 points 5 stars)?
1. You have omitted the table. If by "buoyancy" you mean "buoyant force," then F = (ρw / ρg) * Mg * g = (1.00 / 19.30) * 25kg * 9.8m/s² = 12.7 N 2. Since they are initially at the same height, the pressures under the two pistons must be the same. So 70kg / d² = 1200kg / (2m)² d = 0.483 m When the second man climbs on, the men will drop h and the elephant will rise h' = h * (0.483m / 2m)² = 0.0583 * h, or h = 17.14 * h' At the new equilibrium, 2 * 70kg / (π(0.483m)²/4) = (1200kg + 890kg/m³ * π(2m)²/4 * (h+h')) / π(2m)²/4 2400 kg = 1200kg + 2796kg/m * (h + h') h + h' = 1200kg / 2796kg/m = 0.429 m Sub for h: 17.14h' + h' = 18.14h' = 0.429 m h' = 0.02366 m ≈ 0.024 m = 2.4 cm 3. h = 17.14h' = 0.4056 m ≈ 0.41 m = 41 cm
Can buoyancy be explained by the difference in water pressure on the top and bottom of a solid?
Yes, that’s exactly how buoyancy can be explained. Precisely. The reason anything floats in a fluid is because there’s more pressure pushing it up than there is pushing it down, and the exact amount of buoyancy is directly explained by how much difference there is in pressure.As for your second question, in theory, you’re absolutely correct. If you had a pool of water with a perfectly flat floor, and you placed an object with a perfectly flat base on the floor, so that there was no water between the object and the floor, it would stay on the bottom, no matter how light it was. In real life, some liquid is almost always going to get underneath the cube. In fact, it only needs to get under the edges, then the higher water pressure on the bottom will push the edges up, allowing water to get further underneath and so on.A more realistic example is if you imagine a flexible object with a concave base, rather like a suction cup. If you can place that against the bottom and squish it flat, so the edges stay tight against the floor, then it will most certainly stay on the bottom. We would talk about it as being stuck there, but there’s actually no real adhesion, it’s just held in place by the water pressure.
Physics Question- Calculating pressure/Buoyancy?
10cm. = 0.1 metre. Water depth = 0.2 metre. The top face is submerged 0.1 metre, the bottom face 0.2 metre. Density of water = 1,000kg/m^3. Pressure on top face = (1,000 x g x 0.10) = 980Pa. Pressure on bottom face = (1,000 x g x 0.2) = 1,960Pa. Pressure difference = 980Pa. That is gauge pressure. If you need absolute, add 101,325Pa. to both answers. Now you can do the 2nd one.
What is the similarity between liquid pressure and buoyant force exerted by any liquid?
Bouyant force is nothing but the vectorial addition of force on the body due to liquid pressure.For sake of simplicity, assume a cuboidal body immersed in water .Let's it side be of height 'a' immersed at a depth 'H', such that the top face of the body is at a depth H from the surface of water and the bottom face of the body is at a depth 'H+a'.The force due to liquid pressure on the four side faces cancel each other vectorially. The force on the top face due to liquid pressure[math]Ftop = -rho*g*H*a^2[/math](Assuming a coordinated system with + pointing upwards and - pointing downwards)The force on the bottom face is[math]Fbottom = +rho*g*(H+a)*a^2[/math]Now, net force due to liquid pressure is[math]Fnet = rho*g*a^3[/math]This is the same as buoyant force (volume*g*rho)Note: In all above equations, rho is the density of fluid and not the body
Does anyone can explain the buoyant force and pressure for me?
Pressure is the force per unit area exerted by a given depth of liquid. It is exerted in all directions. the pressure is obtained by the following formula: 1. p = wh Where: p = the pressure w = weight density of the liquid h = height or depth of the liquid from the surface to the level of the point in consideration Buoyancy force is the total upward force exerted by a liquid on a floating object. It is equal to the weight of the liquid displaced by the object. It is obtained by the formula: 2. B = wV Where: B = the buoyancy force w = the weight density of the liquid V = the displaced volume of the liquid, which is also equal to the submerged volume of the object. The submerged volume is that portion of the total external volume of the object which is below the surface of the liquid.