Physics Help???? Roller Coasters?
Consider a roller coaster that moves along the track shown in the figure below. Assume all friction is negligible and ignore the kinetic energy of the roller coaster s wheels. Assume the roller coaster starts with a speed of 20 m/s at point A. Find the speed of the roller coaster when it reaches locations B and C. (Assume hA = 36 m and hB = 18 m.) Vb= ? Vc= ? http://www.webassign.net/giocp2/6-p-032-alt.gif
PLEASE help, Roller coaster physics?
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Roller coaster physics question?
When sitting stationary, the normal force on a rider is equal to her weight, mg. When on the curve, the normal force acting on a rider is: ΣF = mv²/r = n - mg n = m[(v²/r) + g] Of course, at the bottom of the dip, the rider feels 1.5 times her stationary weight, or 1.5mg, so that the normal force on the bottom of the dip is n = 1.5mg. Substituting this into the equation above, you have: 1.5mg = m[(v²/r) + g] 1.5g = (v²/r) + g v = √[0.5gr] = √[0.5(9.8m/s²)(30m)] = 12m/s Hope this helps
Roller coaster physics?
This is an energy problem. Energy cannot be lost, only changed to different forms, because of the conservation of energy law. Therefore, as the motor of the Roller Coaster pulls the carts up the hill, it is converting mechnical energy into potential energy as the carts rise in height. Therefore: work = PE Work = Force x Distance PE = mgh Fd = mgh Because F varies inversely with d, as the distance increases, the force decreases (potential energy remains the same because you are always going up the same height). The motor of the coaster then has to apply less force to pull the motor up. It just needs to pull it for a longer time. If the hill was shorter, then power Power = W/t P = (Fd) / t As the distance become shorter, the time decreases as well. If you were going up the same height (steeper slope) then the force would increase. The power should go down. A force meter would give the greatest reading at the bottom of the hill (after going down) because of centripetal force. Centripetal Force = (mv^2)/r At the bottom of the hill, the curvature is bending up, and since centripetal force always goes towards the center of the circle, the force would be pulling/pushing you up. This would mean that the normal force in which the track pushes you up would be much greater and this you would feel "heavier".
Roller coaster physics problem. Need help thanks?
You are an engineer helping to design a roller coaster that carries passengers down a steep track and around a vertical loop. The coaster's speed must be great enough when at the top of the loop so that the rider stays in contact with the cart and the cart stays in contact with the track. Riders can withstand acceleration no more than a few "g's", where one "g" is 9.8 m/s2. Part A Find the the minimum height of release for the roller coaster to complete the loop. Assume that the radius of the loop is R.
Please help with Physics question asap?! A 955 kg roller coaster trolley comes over the top of a hill with a?
A 955 kg roller coaster trolley comes over the top of a hill with a speed of 1.50 m/s. At the bottom of the hill, the track is in the shape of a circular curve leading to the top of the next hill. If the height of the hill is 25.0 m and the curvature of the track at the bottom of the hill has a radius of 9.50 m, what is the force that the track exerts on the trolley at the lowest point of the hill?
Do you have to have a degree in physics to design a roller coaster?
I think that an education in physics and engineering would be beneficial. But, there is software that you would build the coaster with after your initial design. I have played with coaster software. Not the commercial ones, but the stuff you can download.I’m not sure how you can go about finding a job in the field. I would think that these companies would check the integrity of the design before moving forward.
How do the physics of a roller coaster change when its made out of wood?
The “roller” aspect of a roller coaster is a dynamic phenomenon, and the response of the structure strongly impacts the “feel” of the ride. Generally, metal has little natural damping, whereas wood has quite a bit. For a given member dimension, steel will typically be more stiff than wood, with different natural frequencies and amplitudes of oscillation. In the old days, when designs were largely by experience and general construction practices, the differences could be quite substantial. Now, with detailed computer modeling, both wood and steel coaster characteristics can be pretty well controlled, so differences may be as much intentional as due to material.
Help with a physics question-about a rollercoaster and its loop?
Find minimum speed at the top of the loop ΣFc=mg=mv²/r mass cancels g=v²/r v=√(gr) use mechanical energy to solve for height Potential energy at h turns into potential energy and kinetic energy (Replace second h with 2r PE=PE+KE mgh=mg2r+½mv² mass cancels gh=g2r+½v² replace v²=gr gh=g2r+½gr g cancels h=2r+½r h=5r/2
Physics- Roller Coaster (Velocity) Question?
Ya this is conservation of energy. E before = E after Before, when the coaster is resting, you just have potential energy due to gravity. Pot. Energy = mgh After, since at bottom, there's no more potential energy, but there is kinetic energy because it's moving. Kin. Energy = 1/2 mv^2 so... E bef = E aft mgh = 1/2 mv^2 same mass, so gh = 1/2 v^2 Cheers