What's the point of having so many units of measurement (example: mm, cm, m, km, miles, feet, etc) when one of them would just do fine in life?
Actually, come to think of it, you're right!We definitely don't need so many different measuring units, to me I think that centimeters (cm) may be the best measuring unit around. It's compact, short, and useful for everyday lives, hey I even measure my own height in centimeters, I'm sure that it would be just as easy to understand as measuring an ant or an elephant.Now let's apply it to real life:Let's first measure an atom:Not as small as you might think!So an atom has the length of about 0.1 to 0.5 nanometers, and if we express that in centimeters, it would be...0.00000001 to 0.00000005 cm.Great! Looks simple and understandable.Let's go a little smaller, to the smallest theorized thing ever imaginable. The string (of string theory).And you thought the atom was small?The string of string theory measures to be about...0.000000000000000000000000000000003 cmNow let's go bigger, the distance between our galaxy, the Milky Way, and its closest neighboring galaxy, the Andromeda Galaxy. The distance of about 2.5 million light years would be expressed as about...22,500,000,000,000,00... (about 100,000,000,000 more o)...0,000 cmYep! It seems totally reasonable. I have no idea why they didn't adopt this single measuring unit earlier, it seems like the totally logical thing to do.
Convert 21 inches to appropriate metric units.?
21 inches = 533.4 millimeters 21 inches = 53.34 centimeters 21 inches = 5.334 decimeters 21 inches = 0.5334 meters
The density of aluminum is 2.70 g/cm^3. Express this value in units of kilograms per cubic meter?
The density of aluminum is 2.70 g/cm^3. Express this value in units of kilograms per cubic meter AND pounds per cubic foot. This is what I did for the conversion to kg/m^3: 2.70g/cm^3 x 1000kg/1g x ....(and I got stuck here) these are the answers: 2.70 x 10^3 kg/m^3 and 169 lb/ft^3 Please explain what you do simply so I know how to do it -thank you
You are stuck in this 5x5x5 room, the ceiling, walls and floor of which are made of concrete, and they are 20 cm thick. How will you escape?
���You are stuck in this 5x5x5 room, the ceiling, walls and floor of which are made of concrete, and they are 20 cm thick. How will you escape?”Hello! I’ll be taking the place of Andrew Wang.Wall: a thing perceived as a protective or restrictive barrier.I open the door and walk out.You see, I perceive the door as a restrictive barrier, because I cannot move through it. I remove the restrictive barrier by opening the door, and I walk out.Now, how about the water?Well, you said I was at the end of the ocean. The ocean has a lot of ends, and all of them are next to land! You also never specified how much water is surrounding the box. Conveniently, the door just happens to be facing the shore about a yard away, so I don’t even have to get wet!TL;DR Solution: I open the door and walk onto the shore. I’m assuming this wouldn’t take me 60 minutes, would it?Anti-loophole explanation: Many would say this wouldn’t work because an open door is a gap. Well, the prompt says, “There are no gaps within this room.” There aren’t, but that doesn’t mean there never will be.Improvement for the next time you make a hypothetical scenario: There are a lot of grammatical errors in the prompt that I could have used to my advantage, or to prove that the scenario is impossible. I decided to be courteous and ignore those, but I’m not always that nice.Also, specify the lack of any openings in the future.
What are the advantages of MKS over CGS system of unit?
It mostly depends on what sort of stuff you’re doing. Basic mechanics and mechanical engineering deal with stuff that’s in the size of meters and kilograms, while chemistry is more comfortable in centimeters and grams. Electrical work is mostly MKS if only for units like Joules and Watts, but then they go and make up the VAR as a special power unit that is but isn’t a Watt.That said, CGS has not been developed as fully as MKS…it doesn’t even have its own version of the Watt, as far as I can find you’re stuck with ergs per second. MKS was settled on as the proper SI set generations ago, but cgs sticks around in areas where it fits.
Do people in Europe, who use the metric system, use estimated measurements like, "it's about a foot," or do they say, “roughly 1/3 of a meter”?
In the example given I’d probably say ‘30–35 ’, the word ‘cm.’ being implied. In Denmark where I live, the metric system is absolutely predominant in all walks of life, but there still are a very few curious examples where this is not the whole truth.I work as a carpenter, and although the dimensions of the wood is really measured in mm, we still have a tradition for speaking about it in inches. When I call my local wood-supplier to order some materials, I’ll ask for 1″x6″ if I want a board measuring 25 X 150 mm, or a ‘2 by 4’, if I need a plank of 50 by 100 mm. The length of the plank however, is always mentioned in meters. The employees of such a place know the parlance and never ask questions, but lately I start hearing younger carpenters talking about boards in mm, so it’s probably only a question of time before this century old tradition, which goes back to before the metric system was evolved and implemented, becomes obsolete.Also, boats and yachts are still measured in feet, and if I want to buy a hide for my leatherwork, I pay per square foot. In these cases, I guess, the tradition for measurements has to do with the english connections and traditions, but when it comes to buying wood in inches, I’m pretty sure that the tradition is old danish. An inch is called ‘tomme’ in danish, so the word is completely different from the english word.
A rectangle has area 50,000 cm square. Its length is 5 m. What is its width? What is the answer in metres?
The answer is 100 cm, which is also equal to 1 meter. Here’s how I got it:For a rectangle, Area = Length times Width. In symbols, A = LW.We know A, the area and L, the length, and are asked to find w, the width. If you divide both sides of A=LW by w, we get W= A/L.At this point we need to make sure that A and L are in the same units before dividing L into the A. Now A is in cm^2, but L is in meters. I chose to change L into centimeters.There are 100 cm in a meter. The length l is 5 meters. So l is also 500 cm.W = A/L= 50,000 cm^2 / 500 cm = 100 cm. (Notice that cm^2/cm = cm)I could’ve also chosen to express A in meters^2. One meter is is equal to (100cm)^2 = 10,000 cm^2, so 50,000 cm^2 = 5 meters^2.W=A/L = 5 meters^2/5 meters = 1 meter = 100 cm.