what is the uses of voltmeter?
effectively the question is: when is it necessary to measure a voltage with a handheld device? - to measure voltages provided to electronics over long cables (voltage drop along long cables depending on the current) - measure voltages on circuit boards to check the operation of these boards. - set the thresholds on NIM/CAMAC discriminators, & check the voltage offsets in these units. of course some people call "multimeters" with the catch-all phrase voltmeter. multimeters can also measure resistance values e.g. to check for successful connections of connectors to signal/control cables (a.k.a. cable continuity tests). also, to insure "good grounds". often there is experimental ground and "dirty ground" in an experiment, and if the two are mixed the detector performance can be degraded by line noise. a multimeter can measure the detector ground w.r.t. the dirty ground, and if the result is not "infinity ohms" then the detector is seeing the dirty ground. the multimeter i have can also measure temperatures if i swap out the probe wires for a thermocouple wire... cheers
Question About Settings Gains With Volt Meter?
I Have an Alpine SWE-1043 powered by and Alpine MRP M500. Alpine MRP M500 mono subwoofer car amplifier 300 watts RMS x 1 at 4 ohms (500 watts RMS x 1 at 2 ohms) variable low-pass filter (50-200 Hz, 24 dB/octave) variable bass boost (0-12 dB at 50 Hz) subsonic filter (15 Hz, 24 dB/octave) Alpine SWE-1043 frequency response: 29-1,000 Hz power range: 100-250 watts RMS peak power: 700 watts sensitivity: 84 dB After some research into regards to setting the gains for my amp, I came across Sparky’s (top contributor) Guide. http://www.datafilehost.com/download.php?file=6d26c621 It says that the Volt Meter should read around 31.62 V in regards to my setup’s 250 watt (lowest of the sub/amp combo) to my 4 ohm Impedance. 1) My question is in regards to tone and frequency settings. He offers a 60hz 0db, but other videos use a 50 Hz 0db tone. Which is better or should I stick with the tone that he uses with his excel file where all his calculation are? Secondly my amp has 3 controls Gain, Bass EQ [0db-12db], an the LP Filter [50 Hz-200Hz]. 2) Should I set all these level to the minimum and just adjust the Gain. I read since I’m just powering the sub with the amp, to leave the LP Filter to the Hz I’m using at the deck is this true? If so what’s the best to use (80Hz?) and what should I do the Bass EQ Filter setting. My Head unit has these options Bass Control: Bass Centre Frequency: 60Hz, 80Hz (default), 100Hz, or 200Hz Bass Band Width: 1 (narrow) to 4 (wide) Bass Level: -7 to +7 (+/-14dB in 2dB steps) Treble Control: Treble Centre Frequency: 10kHz (default), 12.5kHz, 15kHz, or 17.5kHz Treble Level: -7 to +7 (+/-14dB in 2dB steps) Which setting would be recommended>? Thanks In Advance!
Why is the resistance of a voltmeter very high?
Voltmeter is supposed to have infinite/very high resistance to avoid loading effect.If the resistance of voltmeter is low, it will start acting as a load itself and draws current from source. Since the voltmeter is connected in parallel to the load, the current drawn by the actual load also changes.As V= IR, when current changes through load, voltage also changes.When voltmeter has very high resistance, it draws very low value of current from the source and the load current is pretty much the same as it was without the voltmeter. Hence voltage across the load is approximately same and we get the correct voltage reading.Let's assume a load resistance of 500 ohms in series with a 100 ohm resistance supplied by a 100 v battery and see the effect of voltmeter resistance in the voltage across load.Actual voltage across the load is 83.33v but lower resistance voltmeter is incorrectly measuring it as 71.428 v.
Circuits / Physics: Please answer the questions correctly A voltmeter with an internal resistance of 100 000 o?
A voltmeter with an internal resistance of 100 000 ohms has less effect on circuit operation than one with an internal resistance of 1 000 000 ohms? a. True.. b. False c. It depends on the circuit voltage d.There is no difference 2. An ammeter has an internal resistance equal to the equivalent resistance of the circuit in which measurements are to be taken. How wll this affect the current? a. There will be no effect b. The current will be decreased in half c. The current will double d. The current will triple 3. the term potential difference refers to the electrical pressure of a voltage source that causes current flow in a circuit a. True b. False c. True only in dc circuits d. None of the above Please answer the questions correctly I need it ASAP (you may put explanations if you like) I'll vote for the best answer Thanks! ^^
Multimeter Electrical Engineering Question?
So in case 2, the 1V. remains constant. Your meter goes across 10k., so its 20k internal resistance is in parallel with 10k. (20 x 10)/(20 + 10) = 6,666.6 ohms. This is in series with 10,000, with 1V. applied across the combination. Current flowing = (1/16,666.6) = 0.00006A. V across 6,666.6 ohm = 0.00006 x 6,666.6, = 0.4V.
Which has more resistance, a galvanometer, a voltmeter, or an ammeter?
Ideal Voltmeter:Since voltmeter is connected in parallel with the element whose voltage is going to be measured,for an ideal voltmeter NO current should flow through it, all current should pass through resister R, so that its(R's) voltage(resistance*current) can be accurately measured by voltmeter.For no flow of current through voltmeter, we need INFINITE Resistance.Ideal Ammeter:Since Ammeter is connected in series with the element whose current is going to be measured.For an ideal Ammeter No voltage should appear across it. All the voltage should be appear across resister so that its(R's) current(voltage/resistance) can be accurately measured.For no appear of voltage accross Ammeter, we need ZERO Resistance.
How can a voltmeter not get killed when measuring the voltage?
In a word? Dielectric strength. OK, two words ;-) Voltmeters are designed to be able to resist arcing to a dead short when operated in the range specified.They typically use a series of resistance, that resistance is VERY high, in the 100 million ohm range. Look for “input impedance” for specifics.At that high a level of resistance, the CURRENT flow is very small.Now, If you were to try to measure voltage while the probes are connected in the CURRENT measuring mode, the impedance is very small. A virtual dead short. In this case, the CURRENT flow is quite high and therefore, the meter will be destroyed in milliseconds. Sometime the meter will have a fuse to protect it but the fuse often takes to long to break the circuit in time to save the meter.
If the internal resistance of the meter were 14 MΩ, what is the voltage across R2?
Internal resistance problem. Suppose that in Figure 3.3 http://www.flickr.com/photos/46645163@N08/4277195852/ , Vo=6V, R1=250kΩ, R2=450kΩ, and Ri=13MΩ. Initially, the voltmeter is disconnected. EXAMPLES: What is the voltage across R2? [Answer: 3.85714285714286 V.] What is the voltage across R2 with the meter connected? [Answer: 3.43276283618582 V.] QUESTION: If the internal resistance of the meter were 14 MΩ, what is the voltage across R2 (in Volts)?
What is the reading of 1,000 sensitivity voltmeter across a 150,000 ohm resistor with 100 volts voltage source?
Whatever the sensitivity of a voltmeter and whatever the load connected, so long as the voltmeter is connected across a voltage source, it will read source voltage only. In this case it will read 100 V, unless the voltage happens to be beyond the range of meter.The question does not mention range of meter, so one can presume that it is able to read 100 V across the source.The question will take different form if the resistance is a part of larger circuit, and is not directly across voltage source. In such case a voltmeter across the voltage will affect the voltage across resistance and reading will change accordingl, depending on the resistance of the meter itself.A voltage source with extremely high 150 K internal resistance is out of question, nor it is implied, and this case is therefore not considered.