Does KCN react with AgNO3?
Lancenigo di Villorba (TV), Italy Yes, it does. I explain you this by means of several examples.... WARNING!! Potassium Cyanide IS A VERY POWERFUL POISON!! DON'T MANIPULE IT IF YOU KNOW NOT THE FUNDAMENTAL SAFETY's RULEs!! DON'T EAT ITS POWDERs, DON'T DRINK ITS AQUEOUS SOLUTIONs!! DON'T ADD ANY ACIDIC STUFFs TO IT!! EXPERIMENT 1) You add some drops of a Silver Nitrate's aqueous solution (e.g. AgNO3) to a Potassium Cyanide's one (e.g. KCN). Obviously, KCN IS IN EXCESS. You would be able to see a little cloudy suspension in the liquid, nonetheless this taint will disappear fastly. The reaction involved follows : AgNO3(aq) + 2 KCN(aq) ---> K[Ag(CN)2](aq) + KNO3(aq) EXPERIMENT 2) You add some drops of a Potassium Cyanide's aqueous solution (e.g. KCN) to a Silver Nitrate's one (e.g. AgNO3). Obviously, AgNO3 IS IN EXCESS. You would be able to see a white-creamish matter which goes down at the vessel-bottom. The reaction involved follows : AgNO3(aq) + 2 KCN(aq) ---> K[Ag(CN)2](aq) + KNO3(aq) AgNO3(aq) + K[Ag(CN)2](aq) ---> ---> Ag[Ag(CN)2](s) + KNO3(aq) ON THE BASIS OF "AgNO3 : KCN's MIXING RATIO", YOU WOULD OBTAIN A WHITISH MATTER OR NOT. I hope this helps you.
Hello :) When ethyl bromide reacts with aqueous KOH, it undergoes hydrolysis. This occurs through the SN 2 mechanics since the substrate is a primary carbon. The OH group from KOH substitutes the Br group from ethyl bromide. The by product is KBr. When ethyl bromide reacts with alcoholic KOH, it undergoes beta elimination . The lone pair on O in OH attracts the hydrogen on the beta carbon( the carbon next to the carbon which has the bromide group) and the potasssium cation attracts the bromide group. The product is ethene and the by products are water and KBr.I'm attaching the reactions here as images.Hope it was helpful :)
What does a chemical reaction of aqueous baking soda with stearic acid produce?
HC is correct.. it is a neutralization The product produced, sodium stearate, is a typical soap...Soaps are usually produced by hydrolyzing triglycerides in fat ( rich in stearic and palmitic acids ) with NaOH, making sodium stearate ( lye soap ) as a major product.
Equation of reaction KCN and water?
KCN is a strong salt : KCN ----> K+ + CN- CN- hydrolizes and the reaction is CN- + H2O <=> HCN + OH- the molecular equation is NaCN + H2O <=> HCN + NaOH
Let me give you a little background and a simple trick on the same.CaCO3 (Calcium carbonate) is a salt which is basic in nature(just assume it as OH-) that means if it finds any acidic H it will fetch it. And how we gonna know whether a salt is basic, acidic or neutral in nature, I have made a trick in a video which is posted below.CH3CO-OH has acidic H (attached with O) and when it is made to react with calcium carbonate (dissolved in H2O), it fetches that acidic H and gives the below overall reaction. I hope you got the overall idea.2CH3COOH + caco3 = ( CH3COO)2Ca +H2O + CO2Source: Avesh Chemistry
The mechanism of reaction between the acidic oxide and the alkali depends on the concentration of the alkali solution.(a) When the alkali (NaOH) solution is very dilute (pH < 8), carbon dioxide will first react with water to form carbonic acid (H2CO3) slowly. The acid thus formed then reacts with the alkali to give sodium hydrogencarbonate (NaHCO3).CO2 + H2O = H2CO3NaOH + H2CO3 = NaHCO3 + H2O(b) When the alkali solution is a fairly concentrated one (pH > 10), carbon dioxide directly reacts with it to form the bicarbonate, which further reacts with the alkali to form sodium carbonate (Na2CO3) as the main product by complete neutralisation.NaOH + CO2 = NaHCO3NaHCO3 + NaOH = Na2CO3 + H2OThus, only when the concentration of the alkali solution is quite low, the reaction proceeds via the formation of carbonic acid. But the acidic oxide is not completely neutralised in this case.
Copper sulfate react with potassium cyanide to produce copper cyanide and potassium sulfate.However in excess KCN solution, it forms the following complex.I hope this helps. :)
Sodium carbonate acts as an alkali because when dissolved in water, it dissociates into the weak acid: carbonic acid and the strong alkali: sodium hydroxide.H20→2H+ +OH-NaCO3→ Na+ + CO3(2-)Net reaction:H2O+NaCO3→H2CO3 + NaOH
This can be explained by the concept of HSAB theory which takes into account the hardness and softness of the reacting species. A harder nucleophile will always try to attack the harder nucleophilic centre. This is because hard-hard interactions are always more preferred than soft-soft interactions followed by hard-soft and soft-hard interactions.For further information on this topic, you can follow the link below.https://chemistry.stackexchange....Now KCN is an ionic species, and generates CN- anion. The negative charge resides on the C-atom and makes it soft. The C-atom adjacent to the halogen in the haloalkane is a soft nucleophilic centre. So, CN- gives alkyl cyanide by forming a C-C bond due to more preferred soft-soft interaction.AgCN, on the other hand is a covalent compound and it does not dissociate easily to give CN-. In this case, the attacking centre will be N-atom, as it is softer as compared to the N-atom in KCN. Hence, we get isocyanide when using AgCN.Hope this helps. :)
This is the reverse reaction of the acid - base neutralization reaction; 2HCl+Ca(OH)2 = CaCl2 + 2H2O. The Ca2+ and Cl- ions will stay in aqueous solution, and the backwards reaction of CaCl2 with H2O just won’t happen. That is, the chemical equilibrium of the above reaction is all the way over to the right. This is because the reverse reaction is energetically very unfavorable.The reverse reaction is equivalent to; H2O = H+ + OH -, that is, it's just the dissociation of water. This has an equilibrium constant, K(w) = 10^-14, at 25C, and so is negligible in solutions of pH 7.