How do you partially differentiate the following function with respect to [math]q[/math]: [math]2e^{(q-h^2+3)^4}[/math]?
Pretend h^2 is just a constant. Then differentiate in the usual way. You have 2e^$^4 where $ stands for q-h^2+3.The question is ambiguous as it’s not clear whether e^$^4 means (e^$)^4 or e^($^4). If we use a superscript rather than ^, the convention would be the second form (the first would be the same as e^(4$)).I’ll assume e^($^4). Just use the chain rule. So differentiating 2e^($^4) gives 2e^($^4). Then multiply by the derivative of $^4, i.e. 4$^3, and then multiply by the derivative of $ itself, i.e. 1 (because h^2 is treated as constant and, obviously 3 IS constant).I’ll leave you to substitute for $ and finish this off.
What is a FICO score and how is it related to a credit report?
You ask a simple question, you deserve a straightforward answer. You asked two as I read it. So here it is.Q. What is a FICO score?A. A FICO score is a way to represent the odds of “goods” versus “bads" events. The usual format lenders want to see is odds of default for their specific loan originations. This allows lenders to decide how much risk of default they will assume when making lending decisions.Q. How is a FICO score related to a credit report?A. The FICO score algorithm uses the past payment information in credit bureau reports to create the score. The more payment problems in a credit report, the lower the score. Consistent on-time payments in full creates higher scores.More Questions? It is easy to point you to very detailed information about these scores and how they are used if you need it. Simply ask.
Personal Q: Do you always have sex on your husband/SO's birthday?
It's his favorite part of his birthday. I don't by any means enjoy giving the kind that isn't the back-door and doesn't get you pregnant, so he looks forward to his birthday because it's a day he KNOWS he's going to get it. Other than that we don't really do much... We go out to dinner and he gets a few presents. Honestly, birthdays don't get much better as the years go on... Sex is the best we can do.
How do I calculate the value of force acting on one charge?
This sounds like homework - you should do your own homework. A better place to get homework help is Physics Forums - The Fusion of Science and CommunityI’ll point you in the right direction … you have the wrong equation: you are asked to find the force on a charge due to a number of other charges and the equation you state is for the electric field due to a point charge.You use Coulombs Law to compute the size and direction of the forces due to each charge separately, then add up the individual forces (remember that forces are vectors) to get the net force in the usual way.Get the size of the force from F = kqQ/r^2 where q and Q are the sizes of the two charges, and r is the distance between them (k is the coulomb constant).You find out the value of r using geometry.You get the direction by remembering that like charges attract, and also doing geometry.This is the same as for mechanical forces you have been working with all along.
What is the proof that Joseph didn't get Mary pregnant with Jesus?
This was a question asked by a girl in my youth group. I am a youth director at a mainline protestant church. I am interested in hearing answers from all sorts of backgrounds and beliefs
How do I calculate the square root of a number in [math]\mathbb{Q}(\sqrt[3]{7})=\{\alpha + \beta\sqrt[3]{7} + \gamma\sqrt[3]{7^2} | \alpha,\beta,\gamma \in \mathbb{Q}\}[/math]?
Actually if you mean finding the roots of polynomials, notice that [math]\Q(\sqrt[3]{7})\subset \C[/math]. Thus find roots the usual way if it is possible, then check if they belong to the field. Unless you mean something more specific this is the answer.
What action will Quora take against that individual user who reported my 3-4 answers repeatedly?
Q: What action will Quora take against that individual user who reported my 3-4 answers repeatedly?Probably none, unless you can make a legitimate case that this is a personal grudge at work, and not simply somebody who diligently reports any violation they see. There are a lot of the latter — how do you know it was the same user anyway? Did they tell you? Or are you just guessing? Don’t be too sure — if you’re not particularly respectful in general, you might well be racking up reports from several people.So, first of all, be certain that your answers are not violations. Since you have chosen to be anonymous and to black out any identifying information (making your image completely worthless to us), nobody can give you any advice on what you might have done wrong either.I’ve seen some pretty questionable decisions by Quora Moderation which leads me to think there’s too much bot work and not enough human oversight, and too many appeals seem to go straight into the circular file, which implies there is too much work for the people employed to handle this. Which means you have to have an iron-clad case; your answers really cannot be questionable when you appeal — if they are, you’ll lose the appeal automatically because moderators don’t have time to waste.So that’s how I’d tackle it; examine your own work with as objective an eye as you can, possibly ask people for help on Collapse Detectives (before appealing, afterwards it is too late), and basically make sure you are as nice and respectful as you can be. Then, if the reporting continues, you’ll actually have a case.
How can you calculate the Coulomb force between the proton and electron of a hydrogen atom?
You can calculate the Coloumb force between any two charged bodies using Coulomb’s Law:F = k (q1*q2/r^2)Where k is Coloumb’s constant:8.99*10^9Nm^2C^-2The electron carries the elementary charge: q = -e.The proton carries the same charge but positive q = eThe value of e is empirically measured to be: 1.602*10^-19 CNow, the r value is a little tricky. r is meant to be the distance between charges. Unfortunately, thanks to quantum physics, the electron could be any distance from the proton. It only has a certain probability of being a given distance.Luckily, physicists account for this by giving a value called the Bohr radius. This is the average or most likely distance a single electron would be from the centre of the single proton in a hydrogen atom. This value is defined as: 5.291772*10^-11mSo we have all our values! Let's plug ’em in and see what we get.F = k (q1*q2/r^2)F = (8.99*10^9Nm^2C^-2)(((-1.602*10^-19 C)(1.602*10^-19 C))/(5.291772*10^-11m)^2)F = (8.99*10^9)(-9.141*10^-18)F = -8.22*10^-8NNote that the value is negative because the proton and electron are attracted to each other. As well, the value would vary depending on where the electron was at any given moment and so this is only the most probable value.
Electrical circuit, differential equations?
You have: L*d²q/dt² + q/C = 0 d²q/dt² + q/(L*C) = 0 This is a second-order, linear, homogeneous ODE with constant coefficients. Solve in the usual way by assuming a solution of the form q = exp(k*t), then q' = k*exp(k*t) and q'' = k²*exp(k*t). Plugging these into the DE and dividing through by the constant factor of exp(k*t) yields the charateristic equation: k² + 1`/(L*C) = 0 k = ± j/sqrt(L*C) where j = sqrt(-1) For convenience, let's define ω = 1/sqrt(L*C), then k = ±ω*j, and the general solution is: q(t) = A*exp(j*ω*t) + B*exp(-j*ω*t) We can get rid of those ugly imaginary exponentials using Euler's relationship, which states that exp(j*z) = cos(z) + j*sin(z). q(t) = A(cos(ω*t) + j*sin(ω*t)) + B*(cos(-ω*t) + j*sin(-ω*t)) Remember that cos(-z) = cos(z) and sin(-z) = -sin(z), so: q(t) = A(cos(ω*t) + j*sin(ω*t)) + B*(cos(ω*t) - j*sin(ω*t)) q(t) = a*cos(ω*t) + b*sin(ω*t) where a = A+B and b = j*(A-B) are just different ways of writing the constants. This is the general solution for the charge on the capacitor as a function of time. The equation for the current is the time derivative of this, or: i(t) = dq/dt = -a*ω*sin(ω*t) + b*ω*cos(ω*t) Obviously, both the charge and current are oscillatory. In this case, we are told that q(0) = 0 and i(0) = 0. We can use these to determine the values of the constants of integration, a and b. q(0) = q_initial = a*1 + b*0 a = q_initial i(0) = 0 = a*0 + b*ω b = 0 so the particular solutions in this case are q(t) = q_initial*cos(ω*t) i(t) = -ω*q_initial*sin(ω*t) The angular (circular) frequency is ω = 1/sqrt(L*C)