I dont know my math how do you divide 1.25 square cubic feet into lenght width and height ?? am building a box?
I think you mean you want to build a box with a volume of 1.25 cubic feet for a speaker, right? The volume of a box (V) is equal to its length (L) times its width (W) times its height (H). Written another way, V = L x W x H. So, one way to build your box would be to make a cube, with all the sides the same length - you've just got to find out what length to use. In that case, L = W = H, and you can make substitutions in the equation. V = L x L x L So, what number times itself times itself gives you V = 1.25 cubic feet? We call that number the "cube root" of V. You can use Google to calculate it for you - just type "cube root of 1.25" into the search box (without the quotes) and it will tell you the answer is L = 1.077. That answer is in decimal feet; you probably want the answer in inches, which will be a little easier to measure. To go from feet to inches, you multiply by 12. L = 1.077 ft x (12 in / 1 ft) L = 12.924 in Whatever you're using to measure probably has fractions of an inch marked, in 1/16 of an inch. So you need to figure out what fraction of an inch 0.924 is. You can multiply 0.924 x 16 to get 14.8, which is pretty close to 15. So, L = 12 + 15/16 in You could go to 13 inches and be pretty close. But, that's just to build a cube. What if a cube won't fit? Maybe your speaker is bigger than 13 inches across. Say you have a 15 inch subwoofer. The face of the box it mounts on will have to be at least 15 in x 15 in, and maybe a little bigger so it has some room. So say you decide to make it 18 in x 18 in. Then you have to figure out the height of the box to give you 1.25 cubic feet of volume. First off, convert 18 inches to 1.5 ft by dividing by 12 in/ft. So you have V = L x W x H 1.25 = 1.5 x 1.5 x H 1.25 = 2.25 x H Then, solve for H by dividing both sides of the equation by 2.25. 1.25 / 2.25 = 2.25 x H / 2.25 0.56 = H So H is 0.56 ft. You can do the same thing as above to figure out that that's around 6 + 3/4 inches. So that's basically it. It's just a little bit of algebra, combined with figuring out what you have to work with - the size of you speaker, and the size of the space you're mounting it in. Hope that helps!
What math do you do to figure out the cubic root of 27 squared?
27 = 3 × 3 × 3 = 3^3 Hence, cubic root of (27) = (27)^(1/3) = ((3)^3)^(1/3) = 3^(3 × (1/3)) = 3^(1) = 3
Since sqrt(x) is a monotonically increasing function it can be estimated by binary search.Square root of a number x will be between 0 and x, so you can do a binary search between those intervals.Here is the code:#include
Most of the answers I have read simply show you some math without explaining what they are doing.In the square root world, there are numbers called perfect squares. Let me give you some examples of perfect squares: 1,4,9,16,25,36,49,64…Notice a pattern? Perfect squares are numbers where if you take the square root of them, you will get a rational number.Most square roots, however, do not have perfect squares. Or in other words, the square roots will be irrational. You don't want to argue with that ;)Let’s take a look at [math]\sqrt{27}[/math]Scary looking thing isn't? We can tell that its going to be around 5 and 6, but closer to five.But we aren't asked to approximate, we are asked to find the square root of 27, so how do we do this. Well, I can tell you that we won't be able to write the answer as a whole number, because it is irrational, but lets look at just the number 27!Let’s see if we can rewrite 27 in such a way that we can simplify this square root.27=3x3x3Well lookie here! We have three threes (Wow that’s a mouthful)We know that 3x3=9, which is a perfect square, so we can take 3x3 (9) out of the square root and put a three outside of it.[math]3\sqrt{3}[/math]Since 3 can't be simplified further, this is our answer.
Why do we use units to measure perimeters, square units for area & cubic units to measure volume?
The thing that makes math easier is to see it. A perimeter is the # of units around the outside and you figure that one way. A square is a one dimensional figure of all the area inside the square so you measure that another way. And a cube is a 3 dimensional square. . .it has depth so you measure that another way. Just draw them out and you will see what they and and realize they can't be measured the same way. Let me try again. A perimeter is like a straight line but it goes around a rectangle. And for a square. . .if I told you a foot long. . .that's a straight line. . .but if I told you a square foot. . .it's 1ft x 1 ft. . .it has height and width and if I told you a cube it would be 1 ft long by 1 ft high by 1 ft deep. . .a cube foot. You are adding dimensions.
Well, Basic but a very good question,I think. As we all know, If there hadn’t been [math]\sqrt{-1} [/math]we would have not been introduced to Imaginary Number and Complex Number. Complex number provides a system for finding roots of Polynomial and Polynomials are used widely as theoretical model for various specialized field that include Electrical Engineering and Quantum Mechanics.Topics utilizing complex numbers include-The investigation of electrical current, wavelength.Liquid flow in relation to obstacles.Analysis of stress on beams.The movement of shock absorbers in cars.The study of resonance of structures.The design of dynamos and electric motors.The manipulation of large matrices used in modeling.In Electrical Engineering,Complex No. are considered as a convenient way to define electric circuits.The best use for imaginary no. is in Telecommunication that we use in our everyday life for internet and for TV Broadcasting. And in many more other fields.Imagine a world having no internet and Satellite Broadcasting is, that we were in before few decades ago,and compare it with now. These would have never possible without [math]\sqrt{-1}[/math] because there would have not been Imaginary and Complex Number.To sum up, our life surely would have not been like we are living now. It would have been a different world.For more information on Role of Complex Number see also-What are some real life applications of complex numbers in engineering and practical life? and What are the applications of complex numbers?