What is the solution to the following chemistry question?
Correct answer is option 3. O3. As Srinath mentioned the process is called ozonolysis. For mechanism see this video Halogenation and ozonolysis of alkynes
What will be the solution of the following Numerical question?
As suggested by Miguel Oliveira, if n(M&C&T)=10, then, n(M&C)=20[math]\implies[/math] n(M&C only)=20–10=10, n(C&T)=30[math]\implies[/math] n(C&T only)=30–10=20, and n(M&T)=25[math]\implies[/math] n(M&T only)=25–10=15.n(M or C or T)=n(M only)+n(C only)+n(T only)+n(M&C only)+n(C&T only)+n(M&T only)+n(M&C&T)=12+5+8+10+20+25=80.Number of students who don’t drink M or C or T=100–80=20.
What is the solution to the 'match the following' question below?
Cute question for an experiment. Let's replace the word "centre of mass" with "Hogwarts point". Now, the question is much more interesting, as you don't have any clue what's a Hogwarts point. Neither do I. But let's do some detective work:b) Possition of Hogwarts point of a sphere: it isn't e, as a sphere doesn't have a base. It isn't f, since a sphare doesn't have medians. It isn't g as it doesn't have diagonals. Hence, it is h.a) Position of Hogwarts point of a cone: It isn't f, as the cone doesn't have medians. It isn't g, as it doesn't have diagonals. Hence, it is e.d) Position of Hogwarts point of a triangle: Triangles don't have diagonals, hence it is f.c) Position of Hogwarts point of a square: The only one left is g.
What is the solution of the following question illustrated below for chemistry 121?
Alka Seltzer is an effervescent tablet containing aspirin (acetylsalicylic acid), citric acid, and NaHCO3. NaHCO3(s) + H+(aq) -> Na+(aq) + H2O(l) + CO2(g) 1) In order for this reaction to occur, you need both reactants. NaHCO3(s) comes from the Alka Seltzer tablet. Where does H+ come from? 2) What would be the visual indication that the reactant did occur?
Help on following question with reactants in solutions?
30.0 ml of a 0.200 M lead nitrate solution contains: 30.0ml x 0.200M = 6.00mMole of Pb(NO3)2 20.0 mL of a .250 M sodium iodide solution contains: 20.0mL x 0.250M = 5.00mMole of NaI a) Since 2.5 mmoles of Pb(NO3)2 can react with 5 mmoles of NaI according to the reaction equation, we would have 3.5mmoles of Pb(NO3)2 un-reacted. Thus 17.5ml of the 0.200 M lead nitrate solution is in excess. b) The molar mass of PbI2 is 461.05 g/mol. The mass of lead iodide formed is: 2.5mmol x 461.05 g/mol = 1.15 g c) Note the total volume is 50.0ml. [Pb++] = 3.5mmol/50.0ml = 0.0700 M [NO3-] = 12mmol/50.0ml = 0.240 M [Na+] = 5.0mmol/50.0ml = 0.100 M You please find the Ksp for PbI2, and calculate the iodide ion concentration as: [I-] = sqrt(Ksp/0.0700) (M)
What is the solution to the following questions on relative velocity?
I can see only question no. 12Velocity is relative we can say when we take 1 body at rest and the other one moving. In your ques. A is moving with 2m/s and B is moving with 10m/s, now it is completely ok if I say B is moving 8m/s RELATIVE to A and A can be considered in a resting state. So B(moving with 8m/) will meet after (distance 8+8+8=16m, speed 8m/s, time=3sec) 3 sec. Hope that helped.
What is the correct answer for the following question?
Sulphur trioxide is the correct answer. Sulphur dioxide on staying in the atmosphere for a while reacts with oxygen to give sulphur trioxide. This conversion of SO2 to SO3 is aided by UV Rays. So you can safely say that SO3 is not a primary pollutant gas.
What will be the solution to this physics question?
I have worked out given problem using pen and paper. I thought it would be easy to solve it on paper rather than writing all the equations in LaTex. Following four images are the solution:Here is the first page: showing all the diagramsHere is the second page: Here is the third page:In the above page, I have used the relation: linear acceleration = angular acceleration * radius linear acceleration in the above problem = [math] a_{1} [/math] angular acceleration = [math] \alpha [/math]radius = a (according to question)Here is the fourth and final page: If you have any doubt regrading the given solution then feel free to ask.